Explanation Given: The path of earth is circle x 2 + y 2 = 16 , 000 , 000 with center of ( 0 , 0 ) and radius of 4000 miles, the path of meteor is hyperbolic 16 , 000 , 000 x 2 − 25 , 000 , 000 y 2 = 4.0 × 10 14 . Assume that x and y are both positive. Formula used: Addition method is used to solve the linear system of equations as well as nonlinear system of equations for one or more variables in which the two equations are added together to eliminate one variable. Calculation: Consider the system of equations, x 2 + y 2 = 16 , 000 , 000 …… (1) 16 , 000 , 000 x 2 − 25 , 000 , 000 y 2 = 4.0 × 10 14 …… (2) Multiply equation (1) by 25 , 000 , 000 and add to equation (2) gives, 25 , 000 , 000 x 2 + 25 , 000 , 000 y 2 = 400 × 10

8th Edition

ISBN: 9780134178967

Author: John Tobey Jr., Jeffrey Slater, Jamie Blair, Jenny Crawford

Publisher: PEARSON

See similar textbooks

Concept explainers

Coordinate Geometry

Coordinate geometry, also known as analytic geometry or Cartesian geometry in classical mathematics, is a type of geometry that is studied using a coordinate system. Coordinate geometry is a branch of mathematics that describes the position of points on …

Videos

Question

Chapter 9.5, Problem 28E

To determine

To calculate: The strike point (x,y) of the given meteor path and earth path and explain it.,

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 9.5, Problem 27E

Chapter 9.5, Problem 29E

Students have asked these similar questions

Tomi flies a drone in a circular path around an object that is 180 yards east and 180 yards south of her position. The drone's path takes it over a point that is 230 yards north and 240 yards west of her. Find an equation for the drone's path. (Assume Tomi is located at the origin, with the horizontal axis running east-west and the vertical axis running north-south)

Anna flies a drone in a circular path around an object that is 170 meters south and 230 meters west of her position. The drone's path takes it over a point that is 170 meters east and 220 meters south of her. Find an equation for the drone's path. (Assume Anna is located at the origin, with the horizontal axis running east-west and the vertical axis running north-south) The drone's path follows the equation (standard form) Submit Question Type here to search

Find the rectangular equation

Chapter 9 Solutions

Intermediate Algebra (8th Edition)

Ch. 9.1 - Prob. 1E Ch. 9.1 - Prob. 2E Ch. 9.1 - Prob. 3E Ch. 9.1 - Prob. 4E Ch. 9.1 - Prob. 5E Ch. 9.1 - Prob. 6E Ch. 9.1 - Prob. 7E Ch. 9.1 - Prob. 8E Ch. 9.1 - Prob. 9E Ch. 9.1 - Find the distance between each pair of points....

Ch. 9.1 - Prob. 11E Ch. 9.1 - Prob. 12E Ch. 9.1 - Prob. 13E Ch. 9.1 - Prob. 14E Ch. 9.1 - Prob. 15E Ch. 9.1 - Find the distance between each pair of points....Ch. 9.1 - Prob. 17E Ch. 9.1 - Find the two values of the unknown coordinate so...Ch. 9.1 - Prob. 19E Ch. 9.1 - Prob. 20E Ch. 9.1 - Prob. 21E Ch. 9.1 - Prob. 22E Ch. 9.1 - Prob. 23E Ch. 9.1 - Prob. 24E Ch. 9.1 - Prob. 25E Ch. 9.1 - Prob. 26E Ch. 9.1 - Prob. 27E Ch. 9.1 - Prob. 28E Ch. 9.1 - Prob. 29E Ch. 9.1 - Prob. 30E Ch. 9.1 - Prob. 31E Ch. 9.1 - Prob. 32E Ch. 9.1 - Prob. 33E Ch. 9.1 - Prob. 34E Ch. 9.1 - Prob. 35E Ch. 9.1 - Prob. 36E Ch. 9.1 - Prob. 37E Ch. 9.1 - Prob. 38E Ch. 9.1 - Prob. 39E Ch. 9.1 - Prob. 40E Ch. 9.1 - Prob. 41E Ch. 9.1 - Prob. 42E Ch. 9.1 - Prob. 43E Ch. 9.1 - Prob. 44E Ch. 9.1 - Prob. 45E Ch. 9.1 - Prob. 46E Ch. 9.1 - Prob. 47E Ch. 9.1 - Prob. 48E Ch. 9.1 - Prob. 49E Ch. 9.1 - Prob. 50E Ch. 9.1 - Prob. 1QQ Ch. 9.1 - Prob. 2QQ Ch. 9.1 - Prob. 3QQ Ch. 9.1 - Prob. 4QQ Ch. 9.2 - Prob. 1E Ch. 9.2 - Prob. 2E Ch. 9.2 - Prob. 3E Ch. 9.2 - Prob. 4E Ch. 9.2 - Prob. 5E Ch. 9.2 - Prob. 6E Ch. 9.2 - Prob. 7E Ch. 9.2 - Prob. 8E Ch. 9.2 - Prob. 9E Ch. 9.2 - Prob. 10E Ch. 9.2 - Prob. 11E Ch. 9.2 - Prob. 12E Ch. 9.2 - Prob. 13E Ch. 9.2 - Prob. 14E Ch. 9.2 - Prob. 15E Ch. 9.2 - Prob. 16E Ch. 9.2 - Prob. 17E Ch. 9.2 - Prob. 18E Ch. 9.2 - Prob. 19E Ch. 9.2 - Prob. 20E Ch. 9.2 - Prob. 21E Ch. 9.2 - Prob. 22E Ch. 9.2 - Prob. 23E Ch. 9.2 - Prob. 24E Ch. 9.2 - Prob. 25E Ch. 9.2 - Prob. 26E Ch. 9.2 - Prob. 27E Ch. 9.2 - Prob. 28E Ch. 9.2 - Prob. 29E Ch. 9.2 - Prob. 30E Ch. 9.2 - Prob. 31E Ch. 9.2 - Prob. 32E Ch. 9.2 - Satellite Dishes Modern satellite dishes intended...Ch. 9.2 - Satellite Dishes Modern satellite dishes intended...Ch. 9.2 - Prob. 35E Ch. 9.2 - Prob. 36E Ch. 9.2 - Prob. 37E Ch. 9.2 - Prob. 38E Ch. 9.2 - Prob. 39E Ch. 9.2 - Prob. 40E Ch. 9.2 - Prob. 41E Ch. 9.2 - Prob. 42E Ch. 9.2 - Prob. 43E Ch. 9.2 - Prob. 44E Ch. 9.2 - Prob. 45E Ch. 9.2 - Prob. 46E Ch. 9.2 - Prob. 1QQ Ch. 9.2 - Prob. 2QQ Ch. 9.2 - Prob. 3QQ Ch. 9.2 - Prob. 4QQ Ch. 9.3 - Prob. 1E Ch. 9.3 - Prob. 2E Ch. 9.3 - Prob. 3E Ch. 9.3 - Prob. 4E Ch. 9.3 - Prob. 5E Ch. 9.3 - Prob. 6E Ch. 9.3 - Prob. 7E Ch. 9.3 - Prob. 8E Ch. 9.3 - Prob. 9E Ch. 9.3 - Prob. 10E Ch. 9.3 - Prob. 11E Ch. 9.3 - Prob. 12E Ch. 9.3 - Prob. 13E Ch. 9.3 - Prob. 14E Ch. 9.3 - Prob. 15E Ch. 9.3 - Prob. 16E Ch. 9.3 - Prob. 17E Ch. 9.3 - Prob. 18E Ch. 9.3 - Prob. 19E Ch. 9.3 - Prob. 20E Ch. 9.3 - Prob. 21E Ch. 9.3 - Prob. 22E Ch. 9.3 - Prob. 23E Ch. 9.3 - Prob. 24E Ch. 9.3 - Prob. 25E Ch. 9.3 - Prob. 26E Ch. 9.3 - Prob. 27E Ch. 9.3 - Prob. 28E Ch. 9.3 - Prob. 29E Ch. 9.3 - Prob. 30E Ch. 9.3 - Prob. 31E Ch. 9.3 - Prob. 32E Ch. 9.3 - Prob. 33E Ch. 9.3 - Prob. 34E Ch. 9.3 - Prob. 35E Ch. 9.3 - Prob. 36E Ch. 9.3 - Prob. 37E Ch. 9.3 - Prob. 1QQ Ch. 9.3 - Prob. 2QQ Ch. 9.3 - Prob. 3QQ Ch. 9.3 - Prob. 4QQ Ch. 9.4 - Prob. 1E Ch. 9.4 - Prob. 2E Ch. 9.4 - Prob. 3E Ch. 9.4 - Prob. 4E Ch. 9.4 - Prob. 5E Ch. 9.4 - Prob. 6E Ch. 9.4 - Prob. 7E Ch. 9.4 - Prob. 8E Ch. 9.4 - Prob. 9E Ch. 9.4 - Prob. 10E Ch. 9.4 - Prob. 11E Ch. 9.4 - Prob. 12E Ch. 9.4 - Prob. 13E Ch. 9.4 - Prob. 14E Ch. 9.4 - Prob. 15E Ch. 9.4 - Prob. 16E Ch. 9.4 - Prob. 17E Ch. 9.4 - Prob. 18E Ch. 9.4 - Prob. 19E Ch. 9.4 - Prob. 20E Ch. 9.4 - Prob. 21E Ch. 9.4 - Prob. 22E Ch. 9.4 - Prob. 23E Ch. 9.4 - Prob. 24E Ch. 9.4 - Prob. 25E Ch. 9.4 - Prob. 26E Ch. 9.4 - Prob. 27E Ch. 9.4 - Prob. 28E Ch. 9.4 - Prob. 29E Ch. 9.4 - Prob. 30E Ch. 9.4 - Prob. 31E Ch. 9.4 - Prob. 32E Ch. 9.4 - Prob. 33E Ch. 9.4 - Prob. 34E Ch. 9.4 - Prob. 1QQ Ch. 9.4 - Prob. 2QQ Ch. 9.4 - Prob. 3QQ Ch. 9.4 - Prob. 4QQ Ch. 9.5 - Prob. 1E Ch. 9.5 - Prob. 2E Ch. 9.5 - Prob. 3E Ch. 9.5 - Prob. 4E Ch. 9.5 - Prob. 5E Ch. 9.5 - Prob. 6E Ch. 9.5 - Prob. 7E Ch. 9.5 - Prob. 8E Ch. 9.5 - Prob. 9E Ch. 9.5 - Prob. 10E Ch. 9.5 - Prob. 11E Ch. 9.5 - Prob. 12E Ch. 9.5 - Prob. 13E Ch. 9.5 - Prob. 14E Ch. 9.5 - Prob. 15E Ch. 9.5 - Prob. 16E Ch. 9.5 - Prob. 17E Ch. 9.5 - Prob. 18E Ch. 9.5 - Prob. 19E Ch. 9.5 - Prob. 20E Ch. 9.5 - Prob. 21E Ch. 9.5 - Prob. 22E Ch. 9.5 - Prob. 23E Ch. 9.5 - Prob. 24E Ch. 9.5 - Prob. 25E Ch. 9.5 - Prob. 26E Ch. 9.5 - Prob. 27E Ch. 9.5 - Prob. 28E Ch. 9.5 - Prob. 29E Ch. 9.5 - Prob. 30E Ch. 9.5 - Prob. 1QQ Ch. 9.5 - Prob. 2QQ Ch. 9.5 - Prob. 3QQ Ch. 9.5 - Prob. 4QQ Ch. 9 - In exercises 1 and 2, find the distance between...Ch. 9 - Prob. 2RP Ch. 9 - Prob. 3RP Ch. 9 - Prob. 4RP Ch. 9 - Prob. 5RP Ch. 9 - Prob. 6RP Ch. 9 - Prob. 7RP Ch. 9 - Prob. 8RP Ch. 9 - Prob. 9RP Ch. 9 - Prob. 10RP Ch. 9 - Prob. 11RP Ch. 9 - Prob. 12RP Ch. 9 - Prob. 13RP Ch. 9 - Prob. 14RP Ch. 9 - Prob. 15RP Ch. 9 - Prob. 16RP Ch. 9 - Prob. 17RP Ch. 9 - Prob. 18RP Ch. 9 - Prob. 19RP Ch. 9 - Prob. 20RP Ch. 9 - Prob. 21RP Ch. 9 - Prob. 22RP Ch. 9 - Prob. 23RP Ch. 9 - Solve each nonlinear system. If there is no real...Ch. 9 - Prob. 25RP Ch. 9 - Prob. 26RP Ch. 9 - Prob. 27RP Ch. 9 - Prob. 1T Ch. 9 - Prob. 2T Ch. 9 - Rewrite the equation in standard form. Identify...Ch. 9 - Prob. 4T Ch. 9 - Prob. 5T Ch. 9 - Prob. 6T Ch. 9 - Prob. 7T Ch. 9 - Prob. 8T Ch. 9 - Prob. 9T Ch. 9 - Prob. 10T Ch. 9 - Prob. 11T Ch. 9 - Prob. 12T Ch. 9 - Prob. 13T Ch. 9 - Prob. 14T Ch. 9 - Prob. 15T Ch. 9 - Prob. 16T

Knowledge Booster

$Algebra$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.

The strike point ( x , y ) of the given meteor path and earth path and explain it.,

Solution Summary: The author explains that the hyperbola and circle do not intersect. Addition method solves linear and nonlinear equations for one or more variables.

Concept explainers

Videos

To calculate: The strike point (x,y) of the given meteor path and earth path and explain it.,

Want to see the full answer?

Chapter 9 Solutions