Explanation Given: The integral is ∬ R x 2 e x 3 + 2 y d x d y and 1 ≤ x ≤ 2 , 1 ≤ y ≤ 3 Approach: Double integral over rectangular region R has specified range for x and y . We can define double integral over rectangular region R as below if a ≤ x ≤ b , c ≤ y ≤ d ∬ R f ( x , y ) d y d x = ∫ a b ∫ c d f ( x , y ) d y d x Or ∬ R f ( x , y ) d x d y = ∫ c d ∫ a b f ( x , y ) d x d y Calculation: Given integral is ∬ R x 2 e x 3 + 2 y d x d y and 1 ≤ x ≤ 2 , 1 ≤ y ≤ 3 We can write integral over rectangular region as ∬ R x 2 e x 3 + 2 y d x d y = ∫ 1 3 ∫ 1 2 x 2 e x 3 + 2 y d x d y On integrating inner integral with respect to x and outer integral with respect to y

2nd Edition

ISBN: 9780321964038

Author: GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher: Pearson Addison Wesley,

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Chapter 9.5, Problem 28E

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The integral is ∬Rx2ex3+2ydxdy and 1≤x≤2,1≤y≤3.

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Chapter 9.5, Problem 27E

Chapter 9.5, Problem 29E

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The integral is ∬ R x 2 e x 3 + 2 y d x d y and 1 ≤ x ≤ 2 , 1 ≤ y ≤ 3 .

Solution Summary: The author explains the value of the integral, which is displaystyleundersetRiint.

Videos

To find:

The integral is ∬Rx2ex3+2ydxdy and 1≤x≤2,1≤y≤3.

Want to see the full answer?

Chapter 9 Solutions

The integral is ∬ R x 2 e x 3 + 2 y d x d y and 1 ≤ x ≤ 2 , 1 ≤ y ≤ 3 .

Solution Summary: The author explains the value of the integral, which is displaystyleundersetRiint.

Videos

To find: The integral is ∬Rx2ex3+2ydxdy and 1≤x≤2,1≤y≤3.

Want to see the full answer?

Chapter 9 Solutions

To find:

The integral is ∬Rx2ex3+2ydxdy and 1≤x≤2,1≤y≤3.