Chapter 9.3, Problem 18PPS

To determine

To solve the given equation using graphing.

Answer to Problem 18PPS

The values of x are 3 and 5 .

Explanation of Solution

Given information :

The function provided is $2x^2-16x=-30$ . This can be written as $2x^2-16x+30=0$

Formula used :

The given equation would be graphed as a function and the points of x-intercepts would be the results. For these points, the x-coordinate shall serve the purpose of the results.

To cross check, put these values in the given equation to confirm that the left-hand side and right-hand side matches.

Calculation :

The graph of the given equation is

In this, the parabola x-intercepts at $\left(3,0\right)$ and $\left(5,0\right)$ .

Now, cross check by putting these values of x-coordinate in the given equation.

  $2x^2-16x+30=0$

This is the given equation.

  $=>2{\left(3\right)}^2-16\left(3\right)+30=0$

Putting $x=3$

  $=>18-48+30=0$

Simplifying this

  $=>0=0$

Now, put the other result.

  $=>2{\left(5\right)}^2-16\left(5\right)+30=0$

Putting $x=5$

  $=>50-80+30=0$

Simplifying this

  $=>0=0$

Thus the test is a success and the result is 3 and 5 .