The vector position of a 3.45 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r₂ = 3î − 2ît² – 6ĵt.(a) Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s.7cm(b) Determine the linear momentum (in g. cm/s) of the system at t = 2.90 s.p =cm(c) Determine the velocity (in cm/s) of the center of mass at t = 2.90 s.cm=cmg. cm/s=(d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.90 s.cm/s²cm/s(e) Determine the net force (in µN) exerted on the two-particle system at t = 2.90 s.FnetμN

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ector position of a 3.45 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r₂ = 3î – 2ît² – 6jt. Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s. cm Determine the linear momentum (in g - cm/s) of the system at t = 2.90 s. 9. cm/s 2. p= Determine the velocity (in cm/s) of the center of mass at t = 2.90 s. 7 Vcm = cm/s

ector position of a 3.45 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r₂ = 3î – 2ît² – 6jt. Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s. cm Determine the linear momentum (in g - cm/s) of the system at t = 2.90 s. 9. cm/s 2. p= Determine the velocity (in cm/s) of the center of mass at t = 2.90 s. 7 Vcm = cm/s

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter10: Systems Of Particles And Conservation Of Momentum

Section: Chapter Questions

Problem 21PQ

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