Essential University Physics: Volume 1 (3rd Edition)
Essential University Physics: Volume 1 (3rd Edition)
3rd Edition
ISBN: 9780321993724
Author: Richard Wolfson
Publisher: PEARSON
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Chapter 9, Problem 91P

A thin rod extends from x = 0 to x = L. It carries a nonuniform mass per unit length μ = Mxa/L1+a, where M is a constant with units of mass, and a is a non-negative dimensionless constant. Find expressions for (a) the rod’s mass and (b) the location of its center of mass. (c) Are your results what you expect when a = 0?

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A wedge of total mass M, of metal with uniform thickness 1 m and uniform mass density p (kg/m³) is shown below. The wedge has a base of length a, and a height of length b. The wedge is supported by two posts. In a previous question, you found that 2CM, the 2 coordinate of the center of 2a mass of the wedge is located at 2. Find an expression for the normal force by post 2 on the wedge. 3 Post 1 Post 2 ΜΕ ΑΣΦ Submit response
The height varies from h to zero according to this function: y(x) = h ( – 1)´ . The constants h and e replace 1.00 m and 3.00 m. There is also a thickness t and a density p. You need two integrals, the total mass and the center of mass. Possibly surprisingly, you don't actually need the numbers t, h, and p. Ax y(x) X The column at x has a mass Am = (density * volume) = y(x) p t Ax. You add all the Am values to get %3D the total mass M. The sum becomes an integral: М — pt y(x) dx For the center of mass, you add each column's x Am, and divide by M: pt Xc х у(x) dx Calculate xc. The only quantity you'll need is e = 5 m.
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Chapter 9 Solutions

Essential University Physics: Volume 1 (3rd Edition)

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