Concept explainers
Check Your Understanding The U.S. Air Force uses “10gs” (an acceleration equal to
The time spend by the Enterprise in accelerating.
Answer to Problem 9.1CYU
The time spend by the Enterprise in accelerating is
Explanation of Solution
Given:
The acceleration is,
Formula used:
The required time is given by,
Here,
Calculation:
Since, the final speed of the Enterprise is
The required time iscalculated as,
Convert the required time to days as,
Conclusion:
The time spend by Enterprise in accelerating is
Want to see more full solutions like this?
Chapter 9 Solutions
University Physics Volume 1
Additional Science Textbook Solutions
Cosmic Perspective Fundamentals
Essential University Physics (3rd Edition)
Applied Physics (11th Edition)
Physics for Scientists and Engineers with Modern Physics
University Physics with Modern Physics (14th Edition)
Physics (5th Edition)
- Check Your Understanding Why would it hurt more if you snapped your hand with a ruler than with a loose spring, even if the displacement of each system is equal?arrow_forwardCheck Your Understanding How high above the bottom of its arc is the particle in the simple pendulum above, when its speed is 0.81 m/s?arrow_forwardplease use the x= Acos(wt+phi) in solving thanks A 5.00 kg partridge is suspended from a pear tree by anideal spring of negligible mass. When the partridge is pulled down0.100 m below its equilibrium position and released, it vibrates with aperiod of 4.20 s. (c) When it is moving upward, how much timeis required for it to move from a point 0.050 m below its equilibriumposition to a point 0.050 m above it? ans= 0.7 seconds just need solutionarrow_forward
- The position with time of an object is given byx(t)=Acos(ωt) If the amplitude is 1.62 m, and the frequency is 1 Hz, what is the object's velocity at 2.3 seconds?arrow_forwardA pendulum consists of a smallobject called a bob hanging froma light cord of fixed length, withthe top end of the cord fixed, asrepresented in Figure CQ7.5. Thebob moves without friction, swingingequally high on both sides. Itmoves from its turning point Athrough point B and reaches itsmaximum speed at point C. (a) Atwhat point does the bob have nonzeroradial acceleration and zero tangential acceleration?What is the direction of its total acceleration at this point?(b) At what point does the bob have nonzero tangentialacceleration and zero radial acceleration? What is thedirection of its total acceleration at this point? (c) At whatpoint does the bob have both nonzero tangential and radialacceleration? What is the direction of its total accelerationat this point?arrow_forwardDoes the mass of the bob affect the period of oscillation of the pendulum? In what way/s?arrow_forward
- A uniform meter sitck swings without friction about a perpedicular axis throught the 30 cm line What is the frequency of small oscillations?arrow_forwardIn the case of a damped pendulum, how would the dyanmics change as a fixed point varied from being a stable spiral, to a stable degenerate node, to a stable node? I know that all the trajectories continue to lose altitude, and that the pendulum goes from whirling clockwise over the top, loses energy, settles to a small oscillation, and eventually comes to rest at the bottom, but wasn't sure if this general description changes based on the variation of fixed points.arrow_forwardSince the speed is not 0 when the block is pushed away from the spring, how can we know if the block stops in the section CD, or if it passes this section and go in the ramp and then back again in direction to the spring? could the block go back and forward a few times before a complete stop somewhere in the CD section?arrow_forward
- Some people modify cars to be much closer to the ground than when manufactured. Should they install stiffer springs? Explain your answer.arrow_forwardHow much energy must the shock absorbers of a 1200-kg car dissipate in order to damp a bounce that initially has a velocity of 0.800 m/s at the equilibrium position? Assume the car returns to its original vertical position.arrow_forwardCheck Your Understanding Galaxies are not single objects. How does the gravitiational force of one galaxy exerted on the “closer” stars of the other galaxy compare to those farther away? What effect would this have on the shape of the galaxies themselves?arrow_forward
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning