Chapter 9, Problem 9.151QP

(a)

Interpretation Introduction

Interpretation:

Equations for the preparation reactions of $\text{HCl}$ and $\text{HF}$ from its metal halides with Sulfuric acid and $\text{HBr}$ from ${\text{PBr}}_{\text{3}}$ with water are should be written and reason for why not preparation of $\text{HBr}$ and $\text{HI}$ are from metal halides with Sulfuric acid should be explained.

Concept introduction:

Preparation of Hydrogen halides:

• Metal halides are reacting with concentrated Sulfuric acid to produce Hydrogen halides.
• In $\text{HBr}$ and $\text{HI}$ are not able to prepared by above method because of Sulfuric acid is a strong oxidizing agent than ${\text{Br}}_{\text{2}}{\text{ and I}}_{\text{2}}$ so it would oxidize ${\text{Br}}^{\text{-}}{\text{ and I}}^{\text{-}}\text{ ions}$ to ${\text{Br}}_{\text{2}}{\text{ and I}}_{\text{2}}$ .
• The alternative method of $\text{HBr}$ preparation is ${\text{PBr}}_{\text{3}}$ is treated with water to produces $\text{HBr}$.

Balanced equation:

• Balanced equation is equation for the chemical reaction, which is written by the number of atoms for each element and total charges of ions are equal in the reaction for in both reactants and the products sides.

(b)

Interpretation Introduction

Interpretation:

Equations for the preparation reactions of $\text{HCl}$ and $\text{HF}$ from its metal halides with Sulfuric acid and $\text{HBr}$ from ${\text{PBr}}_{\text{3}}$ with water are should be written and reason for why not preparation of $\text{HBr}$ and $\text{HI}$ are from metal halides with Sulfuric acid should be explained.

Concept introduction:

Preparation of Hydrogen halides:

• Metal halides are reacting with concentrated Sulfuric acid to produce Hydrogen halides.
• In $\text{HBr}$ and $\text{HI}$ are not able to prepared by above method because of Sulfuric acid is a strong oxidizing agent than ${\text{Br}}_{\text{2}}{\text{ and I}}_{\text{2}}$ so it would oxidize ${\text{Br}}^{\text{-}}{\text{ and I}}^{\text{-}}\text{ ions}$ to ${\text{Br}}_{\text{2}}{\text{ and I}}_{\text{2}}$ .
• The alternative method of $\text{HBr}$ preparation is ${\text{PBr}}_{\text{3}}$ is treated with water to produces $\text{HBr}$.

Balanced equation:

• Balanced equation is equation for the chemical reaction, which is written by the number of atoms for each element and total charges of ions are equal in the reaction for in both reactants and the products sides.

(c)

Interpretation Introduction

Interpretation:

Equations for the preparation reactions of $\text{HCl}$ and $\text{HF}$ from its metal halides with Sulfuric acid and $\text{HBr}$ from ${\text{PBr}}_{\text{3}}$ with water are should be written and reason for why not preparation of $\text{HBr}$ and $\text{HI}$ are from metal halides with Sulfuric acid should be explained.

Concept introduction:

Preparation of Hydrogen halides:

• Metal halides are reacting with concentrated Sulfuric acid to produce Hydrogen halides.
• In $\text{HBr}$ and $\text{HI}$ are not able to prepared by above method because of Sulfuric acid is a strong oxidizing agent than ${\text{Br}}_{\text{2}}{\text{ and I}}_{\text{2}}$ so it would oxidize ${\text{Br}}^{\text{-}}{\text{ and I}}^{\text{-}}\text{ ions}$ to ${\text{Br}}_{\text{2}}{\text{ and I}}_{\text{2}}$ .
• The alternative method of $\text{HBr}$ preparation is ${\text{PBr}}_{\text{3}}$ is treated with water to produces $\text{HBr}$.
• To write the balanced equation for preparation reaction of $\text{HBr}$

Balanced equation:

• Balanced equation is equation for the chemical reaction, which is written by the number of atoms for each element and total charges of ions are equal in the reaction for in both reactants and the products sides.