Concept explainers
(a)
Probability of observing exactly 50 counts in 1min.
(a)
Answer to Problem 9.13P
Probability of observing exactly 50 counts in 1-min is 0.056.
Explanation of Solution
Given:
True mean counting rate is 50 cpm
Mean counts in 1-min,
Exact counts,
Formula used:
Standard deviation,
Probability in normal distribution,
Calculation:
Standard deviation,
Probability for exactly 50 counts
Conclusion:
Probabilityof observing exactly 50 count is 0.056.
(b)
Probability of measuring between 47-57 counts in 1 min.
(b)
Answer to Problem 9.13P
Probability of measuring between 47-57 cpm is 0.68
Explanation of Solution
Given:
Mean counts,
Measuring lie between,
Formula used:
Standard deviation,
Z-score of normal distribution table,
Calculation:
Standard deviation,
Z-score for n = 43,
Z-score for n = 57,
Using Z-score table of normal distribution
Probability of measuring counts between 47-57 cpm
Conclusion:
Probability of measuring between 47-57 cpm is 0.68.
(c)
Probability of measuring more than 57 counts in 1min.
(c)
Answer to Problem 9.13P
Probability of measuring more than 57 counts in 1-min is 0.16.
Explanation of Solution
Given:
True mean counting rate,
Exact count rate n liesbetween,
Formula used:
Standard deviation,
Z-score of normal distribution table,
Calculation:
Standard deviation,
Z-score for n = 43,
Using the Z-score table of normal distribution
The probability of measuring more than 57 counts in 1min.
Conclusion:
Probability of measuring more than 57 counts in 1-min is 0.16.
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Chapter 9 Solutions
Introduction To Health Physics
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