Chemistry: The Science in Context (Fifth Edition)
Chemistry: The Science in Context (Fifth Edition)
5th Edition
ISBN: 9780393614046
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster, Stacey Lowery Bretz, Geoffrey Davies
Publisher: W. W. Norton & Company
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 9, Problem 9.104QP

(a)

Interpretation Introduction

Interpretation: The electronic configuration and the stability of He2+andNe2+ as compared to He2andNe2 is to be predicted.

Concept introduction: When two atomic orbitals come close to each other they lose their identity and form new pair of orbitals knows as molecular orbitals. Among the two molecular orbitals formed one has energy lower than the atomic orbitals is known as bonding molecular orbital and the other has energy higher than the atomic orbitals and is known as antibonding molecular orbital.

To determine: The electronic configuration of He2andNe2 .

(a)

Expert Solution
Check Mark

Answer to Problem 9.104QP

The electronic configuration of He2andNe2 is,

He2=1s)2*1s)2

Ne2=2s)2*2s)22p)22p)4*2p)4*2p)2

Explanation of Solution

Explanation

Helium has two valence electrons.

The total number of valence electrons in He2 is calculated by formula,

Totalnumberofvalenceelectrons=NumberofHeatoms×Valenceelectrons ±Charge=2×20=4

According to the molecular orbital theory the electronic configuration of N2+ is

He2=1s)2*1s)2

Neon has eight valence electrons.

The total number of valence electrons in Ne2 is calculated by formula,

Totalnumberofvalenceelectrons=NumberofNeatoms×Valenceelectrons ±Charge=2×81=16

According to the molecular orbital theory the electronic configuration of Ne2 is

Ne2=2s)2*2s)22p)22p)4*2p)4*2p)2

(b)

Interpretation Introduction

To determine: The stability of the molecular ions formed by removing one electron from He2andNe2 .

(b)

Expert Solution
Check Mark

Answer to Problem 9.104QP

The molecular ions Ne2+ and He2+ are more stable than He2andNe2 .

Explanation of Solution

Explanation

On removing an electron from He2 , it becomes He2+ .

The total number of valence electrons in He2+ is calculated by formula,

Totalnumberofvalenceelectrons=NumberofHeatoms×Valenceelectrons ±Charge=2×21=3

According to the molecular orbital theory the electronic configuration of He2+ is

He2+=1s)2*1s)1

The bond order of He2+ is calculated by formula,

Bondorder=12(NumberofelectronsinbondingmolecularorbitalsNumberofelectroninantibondingmolecularorbitals)=12(21)=0.5

The bond order of He2+ is 0.5 .

On removing an electron from Ne2 it becomes Ne2+ ion.

The total number of valence electrons in Ne2+ is calculated by the formula,

Totalnumberofvalenceelectrons=NumberofNeatoms×Valenceelectrons±Charge=2×81=15

According to the molecular orbital theory the electronic configuration of Ne2+ is,

Ne2+=2s)2*2s)24p)22p)4*2p)4*2p)2

The bond order of Ne2+ is calculated by formula,

Bondorder=12(NumberofelectronsinbondingmolecularorbitalsNumberofelectroninantibondingmolecularorbitals)=12(87)=0.5

The bond order of Ne2+ is 0.5

The stability of an ion or a molecule is directly proportional to its bond order.

Both Ne2+ and He2+ ions have non-zero bond order values.

The molecules He2andNe2 have bond order equal to zero.

Therefore, the molecular ions Ne2+ and He2+ are more stable than He2andNe2 .

The stability of an ion or a molecule is directly proportional to its bond order.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 9 Solutions

Chemistry: The Science in Context (Fifth Edition)

Ch. 9.7 - Prob. 11PECh. 9.7 - Prob. 12PECh. 9.7 - Prob. 13PECh. 9 - Prob. 9.1VPCh. 9 - Prob. 9.2VPCh. 9 - Prob. 9.3VPCh. 9 - Prob. 9.4VPCh. 9 - Prob. 9.5VPCh. 9 - Prob. 9.6VPCh. 9 - Prob. 9.7VPCh. 9 - Prob. 9.8VPCh. 9 - Prob. 9.9QPCh. 9 - Prob. 9.10QPCh. 9 - Prob. 9.11QPCh. 9 - Prob. 9.12QPCh. 9 - Prob. 9.13QPCh. 9 - Prob. 9.14QPCh. 9 - Prob. 9.15QPCh. 9 - Prob. 9.16QPCh. 9 - Prob. 9.17QPCh. 9 - Prob. 9.18QPCh. 9 - Prob. 9.19QPCh. 9 - Prob. 9.20QPCh. 9 - Prob. 9.21QPCh. 9 - Prob. 9.22QPCh. 9 - Prob. 9.23QPCh. 9 - Prob. 9.24QPCh. 9 - Prob. 9.25QPCh. 9 - Prob. 9.26QPCh. 9 - Prob. 9.27QPCh. 9 - Prob. 9.28QPCh. 9 - Prob. 9.29QPCh. 9 - Prob. 9.30QPCh. 9 - Prob. 9.31QPCh. 9 - Prob. 9.32QPCh. 9 - Prob. 9.33QPCh. 9 - Prob. 9.34QPCh. 9 - Prob. 9.35QPCh. 9 - Prob. 9.36QPCh. 9 - Prob. 9.37QPCh. 9 - Prob. 9.38QPCh. 9 - Prob. 9.39QPCh. 9 - Prob. 9.40QPCh. 9 - Prob. 9.41QPCh. 9 - Prob. 9.42QPCh. 9 - Prob. 9.43QPCh. 9 - Prob. 9.44QPCh. 9 - Prob. 9.45QPCh. 9 - Prob. 9.46QPCh. 9 - Prob. 9.47QPCh. 9 - Prob. 9.48QPCh. 9 - Prob. 9.49QPCh. 9 - Prob. 9.50QPCh. 9 - Prob. 9.51QPCh. 9 - Prob. 9.52QPCh. 9 - Prob. 9.53QPCh. 9 - Prob. 9.54QPCh. 9 - Prob. 9.55QPCh. 9 - Prob. 9.56QPCh. 9 - Prob. 9.57QPCh. 9 - Prob. 9.58QPCh. 9 - Prob. 9.59QPCh. 9 - Prob. 9.60QPCh. 9 - Prob. 9.61QPCh. 9 - Prob. 9.62QPCh. 9 - Prob. 9.63QPCh. 9 - Prob. 9.64QPCh. 9 - Prob. 9.65QPCh. 9 - Prob. 9.66QPCh. 9 - Prob. 9.67QPCh. 9 - Prob. 9.68QPCh. 9 - Prob. 9.69QPCh. 9 - Prob. 9.70QPCh. 9 - Prob. 9.71QPCh. 9 - Prob. 9.72QPCh. 9 - Prob. 9.73QPCh. 9 - Prob. 9.74QPCh. 9 - Prob. 9.75QPCh. 9 - Prob. 9.76QPCh. 9 - Prob. 9.77QPCh. 9 - Prob. 9.78QPCh. 9 - Prob. 9.79QPCh. 9 - Prob. 9.80QPCh. 9 - Prob. 9.81QPCh. 9 - Prob. 9.82QPCh. 9 - Prob. 9.83QPCh. 9 - Prob. 9.84QPCh. 9 - Prob. 9.85QPCh. 9 - Prob. 9.86QPCh. 9 - Prob. 9.87QPCh. 9 - Prob. 9.88QPCh. 9 - Prob. 9.89QPCh. 9 - Prob. 9.90QPCh. 9 - Prob. 9.91QPCh. 9 - Prob. 9.92QPCh. 9 - Prob. 9.93QPCh. 9 - Prob. 9.94QPCh. 9 - Prob. 9.95QPCh. 9 - Prob. 9.96QPCh. 9 - Prob. 9.97QPCh. 9 - Prob. 9.98QPCh. 9 - Prob. 9.99QPCh. 9 - Prob. 9.100QPCh. 9 - Prob. 9.101QPCh. 9 - Prob. 9.102QPCh. 9 - Prob. 9.103QPCh. 9 - Prob. 9.104QPCh. 9 - Prob. 9.105QPCh. 9 - Prob. 9.106QPCh. 9 - Prob. 9.107QPCh. 9 - Prob. 9.108QPCh. 9 - Prob. 9.109QPCh. 9 - Prob. 9.110QPCh. 9 - Prob. 9.111QPCh. 9 - Prob. 9.112QPCh. 9 - Prob. 9.113QPCh. 9 - Prob. 9.114QPCh. 9 - Prob. 9.115APCh. 9 - Prob. 9.116APCh. 9 - Prob. 9.117APCh. 9 - Prob. 9.118APCh. 9 - Prob. 9.119APCh. 9 - Prob. 9.120APCh. 9 - Prob. 9.121APCh. 9 - Prob. 9.122APCh. 9 - Prob. 9.123APCh. 9 - Prob. 9.124APCh. 9 - Prob. 9.125APCh. 9 - Prob. 9.126APCh. 9 - Prob. 9.127APCh. 9 - Prob. 9.128APCh. 9 - Prob. 9.129APCh. 9 - Prob. 9.130APCh. 9 - Prob. 9.131APCh. 9 - Prob. 9.132APCh. 9 - Prob. 9.133APCh. 9 - Prob. 9.134APCh. 9 - Prob. 9.135APCh. 9 - Prob. 9.136APCh. 9 - Prob. 9.137APCh. 9 - Prob. 9.138APCh. 9 - Prob. 9.139APCh. 9 - Prob. 9.140APCh. 9 - Prob. 9.141APCh. 9 - Prob. 9.142APCh. 9 - Prob. 9.143AP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
General Chemistry 1A. Lecture 12. Two Theories of Bonding.; Author: UCI Open;https://www.youtube.com/watch?v=dLTlL9Z1bh0;License: CC-BY