(a)
The final velocity of the object.
(a)
Answer to Problem 90AP
The final velocity of the object is
Explanation of Solution
Given information: The mass of the object is
Write the expression of impulse momentum equation.
Here,
Substitute
Thus, the final velocity of the object is
Conclusion:
Therefore, the final velocity of the object is
(b)
The acceleration of the object.
(b)
Answer to Problem 90AP
The acceleration of the object is
Explanation of Solution
Given information: The mass of the object is
Write the expression to calculate the acceleration of the object.
Here,
Substitute
Thus, the acceleration of the object is
Conclusion:
Therefore, the acceleration of the object is
(c)
The acceleration of the object.
(c)
Answer to Problem 90AP
The acceleration of the object is
Explanation of Solution
Given information: The mass of the object is
Write the expression to calculate the acceleration of the object.
Substitute
Thus, the acceleration of the object is
Conclusion:
Therefore, the acceleration of the object is
(d)
The vector displacement of the object.
(d)
Answer to Problem 90AP
The vector displacement of the object is
Explanation of Solution
Given information: The mass of the object is
Write the expression to calculate the vector displacement of the object.
Here,
Substitute
Thus, the vector displacement of the object is
Conclusion:
Therefore, the vector displacement of the object is
(e)
The work done on the object.
(e)
Answer to Problem 90AP
The work done on the object is
Explanation of Solution
Given information: The mass of the object is
Write the expression to calculate the work done on the object.
Here,
Substitute
Thus, the work done on the object is
Conclusion:
Therefore, the work done on the object is
(f)
The final kinetic energy of the object.
(f)
Answer to Problem 90AP
The final kinetic energy of the object is
Explanation of Solution
Given information: The mass of the object is
Write the expression to calculate the final kinetic energy of the object.
Substitute
Thus, the final kinetic energy of the object is
Conclusion:
Therefore, the final kinetic energy of the object is
(g)
The final kinetic energy of the object.
(g)
Answer to Problem 90AP
The final kinetic energy of the object is
Explanation of Solution
Given information: The mass of the object is
Write the expression to calculate the final kinetic energy of the object.
Substitute
Thus, the final kinetic energy of the object is
Conclusion:
Therefore, the final kinetic energy of the object is
(h)
The result of comparison of the answers in part (b), (c) and (f), (g).
(h)
Answer to Problem 90AP
The value of acceleration in part (b), (c) and kinetic energy in part (f), (g) are same.
Explanation of Solution
Given information: The mass of the object is
Write the expression to calculate the acceleration of the object.
Write the expression to calculate the acceleration of the object.
According to the second law of motion,
Substitute
The equation (2) and (8) are same therefore, the value of acceleration in part (b) and (c) are same.
Write the expression to calculate the work done on the object,
Substitute
The equation (10) and (6) are same.
Thus, the value of kinetic energy in part (f) and (g) are same.
Conclusion:
Therefore, the value of acceleration in part (b), (c) and kinetic energy in part (f), (g) are same.
Want to see more full solutions like this?
Chapter 9 Solutions
Physics for Scientists and Engineers With Modern Physics
- In a laboratory experiment, an electron with a kinetic energy of 50.5 keV is shot toward another electron initially at rest (Fig. P11.50). (1 eV = 1.602 1019 J) The collision is elastic. The initially moving electron is deflected by the collision. a. Is it possible for the initially stationary electron to remain at rest after the collision? Explain. b. The initially moving electron is detected at an angle of 40.0 from its original path. What is the speed of each electron after the collision? FIGURE P11.50arrow_forwardA car crashes into a large tree that does not move. The car goes from 30 m/s to 0 in 1.3 m. (a) What impulse is applied to the driver by the seatbelt, assuming he follows the same motion as the car? (b) What is the average force applied to the driver by the seatbelt?arrow_forwardA tennis player receives a shot with the ball (0.060 0 kg) traveling horizontally at 50.0 m/s and returns the shot with the ball traveling horizontally at 40.0 m/s in the opposite direction. (a) What is the impulse delivered to the ball by the tennis racquet? (b) What work does the racquet do on the ball?arrow_forward
- The momentum of an object is increased by a factor of 4 in magnitude. By what factor is its kinetic energy changed? (a) 16 (b) 8 (c) 4 (d) 2 (e) 1arrow_forwardA ball of mass 250 g is thrown with an initial velocity of 25 m/s at an angle of 30 with the horizontal direction. Ignore air resistance. What is the momentum of the ball after 0.2 s? (Do this problem by finding the components of the momentum first, and then constructing the magnitude and direction of the momentum vector from the components.)arrow_forwardIn a laboratory, a cart collides with a wall and bounces back. Figure P11.10 shows a graph of the force exerted by the wall versus time. a. Find the impulse exerted by the wall on the cart. b. What is the average force exerted by the wall on the cart? c. If the cart has a mass of 0.448 kg, what is its change in velocity? d. Make a sketch of the situation. Include a coordinate system and explain the significance of the signs in parts (a) through (c). FIGURE P11.10arrow_forward
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningUniversity Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill