Inquiry into Physics
8th Edition
ISBN: 9781337515863
Author: Ostdiek
Publisher: Cengage
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Chapter 9, Problem 7C
To determine
- Compute the image distance.
- Make a graph of the
p s
- For what value of
s p
- What happens to
p s
- Relate this with the operation of our eye.
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You see a person in the distance. From Figure 1 assume the person of height 'AB’ is
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Figure 1.
(a) The graph below was produced from the data of a thin lens. By analyzing it, what can we saysay about its characteristics, i.e., convergence/divergence and focal length? Explain your reasoning.(b) A thin lens is used to project an image onto a screen. If we cover the right half of the lens,what happens to the projected image? Explain.
Case Example:On one wall there hang a picture 6 ft. x 4 ft. in dimension. On the opposite wall 15 ft. away is a plane mirror. What is the minimum size of the mirror for aperson who is standing 8 ft. away from the mirror to see the whole picture?
(The solution is on the picture)Now, please answer questions 1 and 21. Compute for the number of images produced by a 2 separate mirrors at an angle of 45 degrees if the object is placed between the mirrors.Formula:N = (360/Angle) – 12. A sight testing chart measuring 120 cm x 80 cm, the long dimension being the vertical one is to be viewed by reflection in a plane mirror. Find the smallest size of the mirror that can be used if the chart is 3.25 meters away from the mirror and the observer’s eye is 2.75 meters away from the mirror. The lower edge of the chart is 1.5 meters above the ground. How high must the edge ofthe mirror from the ground?
Chapter 9 Solutions
Inquiry into Physics
Ch. 9 - Give three advantages that the Fresnel lens design...Ch. 9 - Prob. 2OEACh. 9 - Prob. 1PIPCh. 9 - Thomas Young’s conception of the fundamental...Ch. 9 - The shell” of a concept map dealing with lenses...Ch. 9 - Sections 9.6 and 9.7 deal with the phenomena of...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 2QCh. 9 - Prob. 3QCh. 9 - Prob. 4Q
Ch. 9 - Prob. 5QCh. 9 - Prob. 6QCh. 9 - Prob. 7QCh. 9 - Prob. 8QCh. 9 - Prob. 9QCh. 9 - Prob. 10QCh. 9 - Prob. 11QCh. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 15QCh. 9 - Prob. 16QCh. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 20QCh. 9 - Prob. 21QCh. 9 - Prob. 22QCh. 9 - Prob. 23QCh. 9 - Prob. 24QCh. 9 - Prob. 25QCh. 9 - Prob. 26QCh. 9 - Prob. 27QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 29QCh. 9 - Prob. 30QCh. 9 - Prob. 31QCh. 9 - Prob. 32QCh. 9 - Prob. 33QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 35QCh. 9 - Prob. 36QCh. 9 - Prob. 37QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 39QCh. 9 - Prob. 40QCh. 9 - Prob. 41QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 43QCh. 9 - Prob. 44QCh. 9 - Prob. 45QCh. 9 - Prob. 46QCh. 9 - Prob. 47QCh. 9 - Prob. 48QCh. 9 - Prob. 49QCh. 9 - Prob. 50QCh. 9 - Prob. 51QCh. 9 - Prob. 52QCh. 9 - Prob. 53QCh. 9 - Prob. 54QCh. 9 - Prob. 55QCh. 9 - Prob. 56QCh. 9 - Prob. 57QCh. 9 - Prob. 58QCh. 9 - Prob. 59QCh. 9 - Prob. 60QCh. 9 - Suppose a beam of red light from an He-Ne laser...Ch. 9 - In a double-slit interference experiment, a...Ch. 9 - A light ray traveling in air strikes the surface...Ch. 9 - A ray of yellow light crosses the boundary between...Ch. 9 - Prob. 5PCh. 9 - A fish looks up toward the surface of a pond and...Ch. 9 - A camera is equipped with a lens with a focal...Ch. 9 - A 2.0-cm-tall object stands in front of a...Ch. 9 - When viewed through a magnifying glass, a stamp...Ch. 9 - . A person looks at a statue that is 2 m tall. The...Ch. 9 - Prob. 11PCh. 9 - . A small object is placed to the left of a convex...Ch. 9 - . If the object in Problem 12 is moved toward the...Ch. 9 - . (a) In a camera equipped with a 50-mm...Ch. 9 - . The focal length of a diverging lens is...Ch. 9 - . The equation connecting s, p, and f for a simple...Ch. 9 - . If the mirror described in the previous problem...Ch. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 1CCh. 9 - In Section 9.6, we described how the speed of...Ch. 9 - Would the critical angle for a glass—water...Ch. 9 - Prob. 4CCh. 9 - Prob. 5CCh. 9 - Prob. 6CCh. 9 - Prob. 7CCh. 9 - Prob. 8CCh. 9 - Prob. 9CCh. 9 - Prob. 10C
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- in step 1 why is the image distance -4 cm?arrow_forwardIf an 8 cm doll is standing away from a diverging lens and the focal length is 6 m, find the image distance, magnification, and image height from 4, 8, and 10 m away. Determine if the image is real or virtual, inverted or erect, smaller or larger. Use the formula below:arrow_forwardProblem 5: A negative lens L1 is shown. It has a focal length of 100 mm. An object 40 mm in height is placed 170 mm from the lens as shown. Using ray trace rules, dray the three rays to locate the object to scale on the diagram. Locate the image and estimate q, Mr and hima graphically. Next calculate q, MT and himg: Compare to your diagram. Explain any discrepancies. (Drawing to scale, 1 block = 10 mm). 1 Block = 10 mmarrow_forward
- When fully dilated, the pupil of a cat is approximately 12.5 mm wide. For 621 THz light ("T" stands for "tera" and means 1012), determine the minimum angle that can be resolved for the cat eye. Express your answer in degrees. Omin The diagram below shows a cat looking at two trees. The cat is just able to resolve the two trees. The distance between the two trees is 8 m. For the 0min you just determined, determine the distance between the cat & the trees. distance between the cat & the trees =arrow_forwardYou are imaging a pencil through a thin, converging lens as shown in the image below. If p (the distance from the object to the center of the thin lens) is 6.86m and the focal length of the thin lens is 1.4m, how far away (in meters) from the center of the thin lens is the real image located (the real image will be on the right-side of the lens in this particular example illustrated below)? Ray 1 Page Object focal point Converging lens Ray 2 Secondary Ray 3 Ray 1 Ray 3 Principal focal point Real imagearrow_forwardIn order to measure focal length of a diverging lens (L2), we set up the following experiment (as shown in the right figure). It uses another converging lens (L,). An object (o) is placed in front of lens (L,). The image of the object can be seen on a screen (S,), which is located 20cm behind lens (L2). Next, after removing lens (L2) only, the image can be restored (seen) by moving screen 5cm toward lens (L)) to a new location of S-. Please compute the focal length of lens (L2). 5cm 20cmarrow_forward
- Solve and show the solutions by I. Analytical Method - using Lens/Mirror Equation and II. by Graphical Method - Ray Tracing (Indicate your own scale). An object O of a certain height is placed at a distance of 10 mm away from a convex lens and has a focal length of 15 mm. (Round off your final answer up to 2 decimal places.) 1. Where will the image I of this object appear? 2. Determine the magnification. (Round off your final answer up to 2 decimal places.) 3. Describe the image I according to its: a.) size b.) position c.) naturearrow_forwardAn image seen through a convex mirror cut from a sphere of radius 20cm is exactly half size of the object. Where must the object and image be located? Support your work with a ray diagram. Hint: Remember that virtual distances are negative when using the mirror equation. Follow grading rubric. Explain answer.arrow_forwardCould you please show the correct steps to solving this problem? The answer is shown in red, I'm just not sure what steps to take to solve this.arrow_forward
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