Concept explainers
(a)
The increase volume of diamond once it is removed from the chamber.
Answer to Problem 68QAP
The increase volume of diamond once it is removed from the chamber is
Explanation of Solution
Given:
Initial Pressure will act like volume stress
Bulk modulus of diamond
Let
Density of diamond
One carat mass
Volume of 2.8-carat diamond
Formula used:
Bulk Modulus
Here, all alphabets are in their usual meanings.
Calculation:
Substituting the given values in the formula,
Hence, the increase volume of diamond once it is removed from the chamber is
Conclusion:
Thus, the increase volume of diamond once it is removed from the chamber is
(b)
The increase diamond radius.
Answer to Problem 68QAP
The increase diamond radius is
Explanation of Solution
Given:
The increase volume of diamond once it is removed from the chamber is
Let
Formula used:
Here, all alphabets are in their usual meanings.
Calculation:
Substituting the given values in the formula,
Hence, the increase diamond radius is
Conclusion:
Thus, the increase diamond radius is
Want to see more full solutions like this?
Chapter 9 Solutions
COLLEGE PHYSICS
- A horizontal pipe 10.0 cm in diameter has a smooth reduction to a pipe 5.00 cm in diameter. If the pressure of the water in the larger pipe is 8.00 104 Pa and the pressure in the smaller pipe is 6.00 104 Pa, at what rate does water flow through the pipes?arrow_forwardThe gravitational force exerted on a solid object is 5.00 N. When the object is suspended from a spring scale and submerged in water, the scale reads 3.50 N (Fig. P15.24). Find the density of the object. Figure P15.24 Problems 24 and 25.arrow_forwardThe pressure at the bottom of a glass filled with water ( = 1 000 kg/m3) is P. The water is poured out and the glass is filled with ethyl alcohol ( = 806 kg/m3). The pressure at the bottom of the glass is now (a) smaller than P (b) equal to P (c) larger than P (d) indeterminate.arrow_forward
- Two thin-walled drinking glasses having equal base areas but different shapes, with very different cross-sectional areas above the base, are filled to the same level with water. According to the expression P = P0 + gh, the pressure is the same at the bottom of both glasses. In view of this equality, why does one weigh more than the other?arrow_forwardAn incompressible, nonviscous fluid is initially at rest in the vertical portion of the pipe shown in Figure P15.61a, where L = 2.00 m. When the valve is opened, the fluid flows into the horizontal section of the pipe. What is the fluids speed when all the fluid is in the horizontal section as shown in Figure P15.61b? Assume the cross-sectional area of the entire pipe is constant. Figure P15.61arrow_forwardA 50.0-kg woman wearing high-heeled shoes is invited into a home in which the kitchen has vinyl floor covering. The heel on each shoe is circular and has a radius of 0.500 cm. (a) If the woman balances on one heel, what pressure does she exert on the floor? (b) Should the homeowner be concerned? Explain your answer.arrow_forward
- Figure P15.52 shows a Venturi meter, which may be used to measure the speed of a fluid. It consists of a Venturi tube through which the fluid moves and a manometer used to measure the pressure difference between regions 1 and 2. The fluid of density tube moves from left to right in the Venturi tube. Its speed in region 1 is v1, and its speed in region 2 is v2. The necks cross-sectional area is A2, and the cross-sectional area of the rest of the tube is A1. The manometer contains a fluid of density mano. a. Do you expect the fluid to be higher on the left side or the right side of the manometer? b. The speed v2 of the fluid in the neck comes from measuring the difference between the heights (yR yL) of the fluid on the two sides of manometer. Derive an expression for v2 in terms of (yR yL), A1, A2, tube, and mano. FIGURE P15.52arrow_forwardMercury is poured into a U-tube as shown in Figure P15.17a. The left arm of the tube has cross-sectional area A1 of 10.0 cm2, and the right arm has a cross-sectional area A2 of 5.00 cm2. One hundred grams of water are then poured into the right arm as shown in Figure P15.17b. (a) Determine the length of the water column in the right arm of the U-tube. (b) Given that the density of mercury is 13.6 g/cm3, what distance h does the mercury rise in the left arm?arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning