World of Chemistry
World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
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Chapter 9, Problem 62A
Interpretation Introduction

Interpretation :

Maximum ammonia yielding reaction must be chosen from the given list.

Concept Introduction :

1 mol nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

Expert Solution & Answer
Check Mark

Answer to Problem 62A

Correct answer: Option D is correct.

Explanation of Solution

Reason for correct option: Option D is correct because in all the reaction amount of hydrogen is 3 moles and excess nitrogen is given. So same amount of ammonia (2 moles) will be produced in all the reactions. Some of the reactions will have excess nitrogen.

Conclusion

Reasons for incorrect options: Option A is incorrect as in this reaction 2 moles of ammonia will be produced which is not only the reaction in which maximum ammonia is produced.

Option B is incorrect as in this reaction 2 moles of ammonia will be produced which is not only the reaction in which maximum ammonia is produced.

Option C is incorrect as in this reaction 2 moles of ammonia will be produced which is not only the reaction in which maximum ammonia is produced.

Chapter 9 Solutions

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