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Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
15th Edition
ISBN: 9781119231318
Author: Morris Hein
Publisher: Wiley (WileyPLUS Products)
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Chapter 9, Problem 51AE
Interpretation Introduction
Interpretation:
The salt solution, which produces the larger amount of
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Contents
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2. When 50.0 mL of a 0.300 M AGNO; solution is added to 250.0 mL, 0.050 M of
MgCl, a AgCl precipitate forms immediately. If the recovered AgCl is found to
have a mass of 1.00 g,
a. Calculate the % yield
b. What is the concentration of Ag" and Cl ions in the final solution?
In which of the following solutions will a precipitate form?
(i) an AgNO3 solution added to a NaCl solution
(ii) S2- ions added to a Cu2+ solution
(iii) phosphate ions added to a solution containing Mg2+
(iv) Cu2+ added to a solution containing Mg2+
The answer is i, ii, iii.
Barium (Ba) can be analyzed in solutions by forming BaSO4 (s) precipitate.
Ba (2+) + SO4(2-) --> BaSO4 (s)
When a 1.0 g sample of a barium compound was treated with excess H2SO4, it formed 0.605 g of BaSO4 (s) precipitate.
a. What is the percentage (by weight) of barium (Ba+2) in the barium compound?
b. What is the identity of this sample barium compound?
Chapter 9 Solutions
Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
Ch. 9.1 - Prob. 9.1PCh. 9.2 - Prob. 9.2PCh. 9.2 - Prob. 9.3PCh. 9.3 - Prob. 9.4PCh. 9.3 - Prob. 9.5PCh. 9.4 - Prob. 9.6PCh. 9.4 - Prob. 9.7PCh. 9.5 - Prob. 9.8PCh. 9.5 - Prob. 9.9PCh. 9.5 - Prob. 9.10P
Ch. 9 - Prob. 1RQCh. 9 - Prob. 2RQCh. 9 - Prob. 3RQCh. 9 - Prob. 4RQCh. 9 - Prob. 5RQCh. 9 - Prob. 6RQCh. 9 - Prob. 7RQCh. 9 - Prob. 8RQCh. 9 - Prob. 1PECh. 9 - Prob. 2PECh. 9 - Prob. 3PECh. 9 - Prob. 4PECh. 9 - Prob. 5PECh. 9 - Prob. 6PECh. 9 - Prob. 7PECh. 9 - Prob. 8PECh. 9 - Prob. 9PECh. 9 - Prob. 10PECh. 9 - Prob. 11PECh. 9 - Prob. 12PECh. 9 - Prob. 13PECh. 9 - Prob. 14PECh. 9 - Prob. 15PECh. 9 - Prob. 16PECh. 9 - Prob. 17PECh. 9 - Prob. 18PECh. 9 - Prob. 19PECh. 9 - Prob. 20PECh. 9 - Prob. 21PECh. 9 - Prob. 22PECh. 9 - Prob. 23PECh. 9 - Prob. 24PECh. 9 - Prob. 25PECh. 9 - Prob. 26PECh. 9 - Prob. 27PECh. 9 - Prob. 28PECh. 9 - Prob. 29PECh. 9 - Prob. 30PECh. 9 - Prob. 31PECh. 9 - Prob. 33AECh. 9 - Prob. 34AECh. 9 - Prob. 35AECh. 9 - Prob. 36AECh. 9 - Prob. 37AECh. 9 - Prob. 39AECh. 9 - Prob. 42AECh. 9 - Prob. 43AECh. 9 - Prob. 44AECh. 9 - Prob. 45AECh. 9 - Prob. 46AECh. 9 - Prob. 47AECh. 9 - Prob. 48AECh. 9 - Prob. 49AECh. 9 - Prob. 50AECh. 9 - Prob. 51AECh. 9 - Prob. 52AECh. 9 - Prob. 53AECh. 9 - Prob. 54AECh. 9 - Prob. 55AECh. 9 - Prob. 56AECh. 9 - Prob. 57AECh. 9 - Prob. 59CECh. 9 - Prob. 60CECh. 9 - Prob. 61CECh. 9 - Prob. 62CECh. 9 - Prob. 63CE
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- A 50.0 ml solution contains only Na2SO4 (MW 142.04 g/mole). If 40.0 ml of 0.25 M BaCl2 is needed to precipitate all the SO42- as BaSO4, what mass of Na2SO4 was in the original solution? What is the concentration of Cl- in the final solution?arrow_forwardNet ionic equation of FeCl3 + Na2Sarrow_forwardcalcium hydroxide in water to form solid according t this equation Al, (GDWglaq)+3Ca(OH),caq)-> 2A\DH,G) +3CaSOAlaq If she reacts 20 moles of calcium hydrOxide With ample aluminum sulfate, had many moles ot Precipitate can She make? A. B1.0 1.3 D 2.0 E4.0arrow_forward
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