College Physics
OER 2016 Edition
ISBN: 9781947172173
Author: OpenStax
Publisher: OpenStax College
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Chapter 9, Problem 31PE
To determine
The force exerted by the biceps muscles.
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A woman is standing erect and with her elbow flexed 90°. She has an 80 N load in her hand and it has a 0.25 m lever arm to the elbow. Her biceps creates 800 N of force and it has a 0.02 m lever arm to the elbow. The type of contraction in the biceps is:
Group of answer choices
concentric
isometric
really big
eccentric
This a not graded assignment, it is a question on a practice exam.
Please do question 7.
A bodybuilder holds a dumbbell of weight Wd. His arm is horizontal and weighs 34 N. The deltoid muscle is assumed to be the only muscle acting and is attached to the arm as shown. The maximum force M→ that the deltoid muscle can supply has a magnitude of 2976 N. The distances that locate where the various forces act on the arm. What is the weight of the heaviest dumbbell that can be held by the bodybuilder? Note: Express your answer in whole numbers. No unit is required for the final answer.
Chapter 9 Solutions
College Physics
Ch. 9 - What can you say about the velocity of a moving...Ch. 9 - Under what conditions can a rotating body be in...Ch. 9 - What three factors affect the torque created by a...Ch. 9 - A wrecking ball is being used to knock down a...Ch. 9 - Mechanics put a length of Pipe over the handle of...Ch. 9 - Prob. 6CQCh. 9 - Explain the need for tall towers on a suspension...Ch. 9 - When visiting some countries, you may see a person...Ch. 9 - Prob. 9CQCh. 9 - Prob. 10CQ
Ch. 9 - Why are the forces exerted on the outside world by...Ch. 9 - Explain why the forces in our joints are several...Ch. 9 - Why are the forces exerted on the outside world by...Ch. 9 - Explain why the forces in our joints are several...Ch. 9 - Certain of dinosaurs were bipedal (walked on two...Ch. 9 - Swimmers and athletes during competition need to...Ch. 9 - If the maximum force the biceps muscle can exert...Ch. 9 - Suppose the biceps muscle was attached through...Ch. 9 - Explain one of the reasons why pregnant women...Ch. 9 - (a) When opening a door, you push on it...Ch. 9 - When tightening a bolt, you push perpendicularly...Ch. 9 - Two children push on opposite sides of a door...Ch. 9 - Use the second condition for equilibrium (net =0 )...Ch. 9 - Repeat the seesaw problem in Example 9.1 with the...Ch. 9 - Prob. 6PECh. 9 - Two children of mass 20.0 kg and 30.0 kg sit...Ch. 9 - Prob. 8PECh. 9 - A person carries a plank of wood 2.00 m long with...Ch. 9 - Prob. 10PECh. 9 - Prob. 11PECh. 9 - Prob. 12PECh. 9 - Prob. 13PECh. 9 - Prob. 14PECh. 9 - Prob. 15PECh. 9 - Prob. 16PECh. 9 - To get up on the roof, a person (mass 70.0 kg)...Ch. 9 - Prob. 18PECh. 9 - Prob. 19PECh. 9 - Suppose you needed to raise a 250-kg mower a...Ch. 9 - Prob. 21PECh. 9 - Prob. 22PECh. 9 - Prob. 23PECh. 9 - Prob. 24PECh. 9 - Prob. 25PECh. 9 - Prob. 26PECh. 9 - Prob. 27PECh. 9 - Prob. 28PECh. 9 - Prob. 29PECh. 9 - Prob. 30PECh. 9 - Prob. 31PECh. 9 - Prob. 32PECh. 9 - Prob. 33PECh. 9 - Prob. 34PECh. 9 - Prob. 35PECh. 9 - Integrated Concepts Suppose we replace the 4.0-kg...Ch. 9 - Prob. 37PECh. 9 - You have just planted a sturdy 2-m-tall palm tree...Ch. 9 - Unreasonable Results Suppose two children are...Ch. 9 - Construct Your Own Problem Consider a method for...Ch. 9 - Prob. 1TPCh. 9 - Prob. 2TPCh. 9 - Prob. 3TPCh. 9 - Prob. 4TPCh. 9 - Prob. 5TPCh. 9 - Prob. 6TPCh. 9 - Prob. 7TPCh. 9 - Prob. 8TPCh. 9 - Prob. 9TPCh. 9 - Prob. 10TPCh. 9 - Prob. 11TP
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- A bodybuilder holds a dumbbell of weight Wd. His arm is horizontal and weighs 38 N. The deltoid muscle is assumed to be the only muscle acting and is attached to the arm as shown. The maximum force M→ that the deltoid muscle can supply has a magnitude of 2849 N. The distances that locate where the various forces act on the arm. What is the weight of the heaviest dumbbell that can be held by the bodybuilder? Note: Express your answer in whole numbers. No unit is required for the final answer. M 13.0° +y Wa Wa 0.150 m 0.280 m 0.620 m (b) Free-body diagram of the arm M Deltoid Dumbbell 13.0° muscle Axis W Wa Shoulder joint (a) (c) Round your answer to 0 decimal places. 11 minutes remainingarrow_forwardThe plank is a great way to strengthen abdominal, back, and shoulder muscles. You can also use this exercise position to locate your center of gravity. Holding plank position with a scale under his toes and another under his forearms, one athlete measured that 66.0% of his weight was supported by his forearms and 34.0% by his toes. (That is, the total normal forces on his forearms and toes were 0.660w and 0.340w, respectively, where w is the athlete’s weight.) He is 1.80 m tall, and in plank position the distance from his toes to the middle of his forearms is 1.53 m. How far from his toes is his center of gravity?arrow_forwardA person places his hand palm downward on a scale and pushes down on the scale until it reads 96.0 N. The triceps muscle is responsible for this arm extension force. Find the force exerted by the triceps muscle. The bottom of the triceps muscle is 2.50 cm to the left of the elbow joint, and the palm is pushing at approximately 29.0 cm to the right of the elbow joint. P 96.0 N 2.50 cm and Q = 29.0 cm. where P =arrow_forward
- A person places his hand palm downward on a scale and pushes down on the scale until it reads (8.31x10^1) N. The triceps muscle is responsible for this arm extension force. Find the force (in N) exerted by the triceps muscle. The bottom of the triceps muscle is 2.50 cm to the left of the elbow joint, and the palm is pushing at approximately 35.0 cm to the right of the elbow joint. (please ignore the number 96 shown in the scale). Give your answer with three significant figures.arrow_forwardConsider a horizontal forearm. On one end of the forearm is the elbow, and on the other end is the hand. The forearm has a mass of 2.08 kg. The distance from the elbow to the hand is 39.7 cm. If the biceps muscle connects to the forearm a distance of 4.73 cm from the elbow, and the biceps muscle can supply a maximum force of 1.417E+3 N (with the forearm in a horizontal position), what is the maximum mass (in kg) that the person can hold?arrow_forward1 b F2 1 1 FR F1 b. The figure above shows a crane tower on site at the HWY 1 expansion and Stoney Trail extension in NW Calgary. You are a design engineer working for the company supplying cranes for the contractors and you have been asked to evaluate the tower design. The crane tower supporting the pulley is designed so that the resultant force from the cable tension running over the pulley is oriented along the tower axis. Note: The tension in the cable is the same on both sides so ||Fill = ||F2l|| = T.arrow_forward
- Triceps 14- 101 2.4 cm Muscles can only contract, so they occur in pairs. In the arm, the biceps muscle is a flexor-that is, it closes the limb. The triceps muscle is an extensor that opens the limb. This configuration is typical of skeletal muscles, bones, and joints in humans and other vertebrates. Most skeletal muscles exert much larger forces within the body than the limbs apply to the outside world. Imagine that a person is pushing down on a tabletop with their hand as shown in the figure. If the person applies a downward force of 70 N with their hand (thats about 16 lbs of force) what force does the triceps tendon exert on the lower arm? The unknown force is indicated by the red arrow in the figure. Ignore the weight of the arm in your calculation. O 5.6 N 70 N 280 N 875 N 30 cm 945 Narrow_forwardA 35 N forearm (we are ignoring the hand for this problem) are held at a 45 deg angle to the vertically oriented humerus. The COM of the forearm is located at a distance of 15 cm from the joint center at the elbow, and the elbow flexor muscles have a 3 cm moment arm. How much force must be exerted by the elbow flexor muscles to maintain this position? Hide answer choices A A 35 N C 81.7 N 123.7 N D 371 N Fm 45° * --Wt₂arrow_forwardThe patellar tendon attaches to the tibia at the tibial tuberosity at a perpendicular distance of 4.91 cm from the center of the knee joint. During an isometric contraction, the lower leg is held at an angle of 35° of knee extension with a 400 N weight strapped to the ankle. The weight is 52 cm from the knee joint center. What is the force produced by the quadriceps to hold this position? Ignore the weight of the leg.arrow_forward
- Remember to show all work Fp For the glenohumeral joint shown above, there are two muscle force: F, (deltoid) and Fs (supraspinatus) with values as follows: Fp = 400 N acting at an angle of 10 degrees with respect to vertical Fs= 200 N acting at an angle of 25 degrees with respect to horizontal a) By adding these force vectors, solve for the net force acting on the glenohumeral joint (magnitude). The opposite of this net force is referred to as the joint reaction force. b) What is the predominant orientation of this joint reaction force (ie, superior, inferior, medial, lateral, anterior or posterior)? c) What shoulder muscle might be able to counterbalance this force? Your text from your A&P course will be helpful here.arrow_forwardAn individual leans forwards to pick up a box of 100 N. The weight of his upper body has a magnitude of 450 N. The back is pivoting around the base of the vertebral column. Consider the back of the individual as a rigid bar that is controlled by a muscle with an angle of 12° (See picture, d = trunk-head distance = 1 m).a) Calculate the magnitude of muscle force required to lift the box.b) Calculate the magnitude of the force at the base of the vertebral column. Hints: For (a) solve the equilibrium of moments, i.e. what force is required in the muscle to balance out the moments acting around the base of the spine.For (b), solve the equilibrium of forces acting on the spine, including the muscle force you’ve just calculated, in x and y separately. There are two extra forces not shown in the diagram: x and y contact forces acting at the base of the spine. These are whatever is needed to keep the total forces acting on the spine = 0 (so the spine isn’t accelerating off in some…arrow_forwardThe 465-kg uniform I-beam supports the load shown. Determine the reactions at the supports. Answers: Ax= Ay= By= i -5.9 m- 3.1 m 200 kg zzzarrow_forward
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