Briefly explain how the larger jovian moons tend to differ in general from the smaller ones. How does the formation process of the moons explain these differences?
The difference between large Jovian moons from the smaller ones.
Answer to Problem 1RQ
The large Jovian moon is different from the small Jovian moon in appearance and the properties by which they orbit around the planet.
Explanation of Solution
The large Jovian moon is different from the small Jovian moon in appearance and the properties by which they orbit around the planet.
Most of the small moon such as (Calypso, Pandora, Phoebe, Janus)are irregular in shape and sometimes they resemble to potatoes, peanuts and other snacks while mostly all the large moons are spherical in shape such as (Titan, Ganymede, Io , Europa).
The small objects have very less gravity, and it is very weak that it cannot force the rigid material by which the moons are made of to form the sphere.
Many small moons are fragments of large moons that are broken apart so they have similar characteristic as the larger moon.
The two largest moons, Titan of Saturn and Ganymede of Jupiter are bigger than Mercury. Almost all of the moderate to large size moons orbit around the planet in the same way as planets orbit around the sun.
Many of the small moons also have orbits that are extremely elliptical to their host planets and some moons have retrograde motion too.
Conclusion:
Thus, the large Jovian moon is different from the small Jovian moon in appearance and the properties by which they orbit around the planet.
Want to see more full solutions like this?
Chapter 9 Solutions
Life in the Universe (4th Edition)
Additional Science Textbook Solutions
Campbell Essential Biology with Physiology (5th Edition)
Introductory Chemistry (6th Edition)
College Physics: A Strategic Approach (3rd Edition)
Campbell Biology in Focus (2nd Edition)
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Anatomy & Physiology (6th Edition)
- No chatgpt pls will upvotearrow_forward13.87 ... Interplanetary Navigation. The most efficient way to send a spacecraft from the earth to another planet is by using a Hohmann transfer orbit (Fig. P13.87). If the orbits of the departure and destination planets are circular, the Hohmann transfer orbit is an elliptical orbit whose perihelion and aphelion are tangent to the orbits of the two planets. The rockets are fired briefly at the depar- ture planet to put the spacecraft into the transfer orbit; the spacecraft then coasts until it reaches the destination planet. The rockets are then fired again to put the spacecraft into the same orbit about the sun as the destination planet. (a) For a flight from earth to Mars, in what direction must the rockets be fired at the earth and at Mars: in the direction of motion, or opposite the direction of motion? What about for a flight from Mars to the earth? (b) How long does a one- way trip from the the earth to Mars take, between the firings of the rockets? (c) To reach Mars from the…arrow_forwardNo chatgpt pls will upvotearrow_forward
- a cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?arrow_forwardCalculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Give in the answer window the calculated repeated experiment variance in m/s2.arrow_forwardNo chatgpt pls will upvotearrow_forward
- 2. Consider the situation described in problem 1 where light emerges horizontally from ground level. Take k = 0.0020 m' and no = 1.0001 and find at which horizontal distance, x, the ray reaches a height of y = 1.5 m.arrow_forward2-3. Consider the situation of the reflection of a pulse at the interface of two string described in the previous problem. In addition to the net disturbances being equal at the junction, the slope of the net disturbances must also be equal at the junction at all times. Given that p1 = 4.0 g/m, H2 = 9.0 g/m and Aj = 0.50 cm find 2. A, (Answer: -0.10 cm) and 3. Ay. (Answer: 0.40 cm)please I need to show all work step by step problems 2 and 3arrow_forwardFrom number 2 and 3 I just want to show all problems step by step please do not short cut look for formulaarrow_forward
- Foundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningAstronomyPhysicsISBN:9781938168284Author:Andrew Fraknoi; David Morrison; Sidney C. WolffPublisher:OpenStax
- Horizons: Exploring the Universe (MindTap Course ...PhysicsISBN:9781305960961Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningAn Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning