Delmar's Standard Textbook Of Electricity
7th Edition
ISBN: 9781337900348
Author: Stephen L. Herman
Publisher: Cengage Learning
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Chapter 9, Problem 1RQ
To what is the turning force of a d’Arsonval meter movement proportional?
Expert Solution & Answer
To determine
The quantity to which the turning force of a d’Arsonval meter movement proportional to?
Answer to Problem 1RQ
The turning force of a d’Arsonval meter movement is proportional to the strength of the magnetic field developed in the current carrying coil.
Explanation of Solution
Description:
The underlying principle behind operation of the d’Arsonval meter movementis that like magnetic poles repel each other. The turning force of depends on the repulsion of magnetic fields. A magnetic field is created around the coilas current passes through it.
The flow of current is such that the polarity of the permanent magnet and that of the magnetic pole created around the coil is the same. As like magnetic poles repel each other, the coil is deflected away from the pole of the magnet. A spring provides the damping movement to the turning of the coil. The turning distance against the spring is proportional to the strength of the magnetic field developed in the current carrying coil.
Conclusion:
The quantity on which the turning force of a d’Arsonval meter movement is dependant has been explained.
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Students have asked these similar questions
A linear electrical load draws 11 A at a 0.72 lagging power factor./1 153. When a capacitor is connected, the line current dropped to 122 A and the power factor
improved to 0.98 lagging. Supply frequency is 50 Hz.
a. Let the current drawn from the source before and after introduction of the capacitor be 11 and 12
respectively. Take the source voltage as the reference and express 11 and 12 as vector
quantities in polar form.
b. Obtain the capacitor current, IC = 12 - 11, graphically as well as using complex number
manipulation. Compare the results.
c. Express the waveforms of the source current before (11(t)) and after (12(t)) introduction of the
capacitor in the form Im sin(2лft + 0). Hand sketch them on the same graph. Clearly label your
plots.
d. Analytically solve i2(t) – i1(t) using the theories of trigonometry to obtain the capacitor current
in the form, ¡C(t) = ICm sin(2πft + OC). Compare the result with the result in Part b.
Transmission line data:Data:• Active power of the load (P): 50 kW• Power factor of the load (PF): 0.8 (lagging)• Line-to-line voltage at the load (V_LC): 13.8 kV• Line resistance (R): 2 Ω• Line inductance (L): 0.8 H• Line capacitance (C): 0.0003 F• Required series compensation: 60% of the line impedance.• Line length: 250 kmDetermine:1. Characteristic impedance and propagation constant.2. The generalized long line constants A, B, C, D.3. Total voltage, current and power at the generating end.4. Voltage regulation.5. Parameters A, B, C, D of the compensation circuit.6. New generalized constants of the power system afterseries compensation.7. Conclusion of the results obtained.
3.18
In a single-phase half-wave ac-dc converter, the average value of the load
current is 1.78 A. If the converter is operated from a 240 V, 50 Hz supply
and if the average value of the output voltage is 27% of the maximum
possible value, calculate the following, assume the load to be resistive.
(a) Load resistance
(b) Firing angle
(c) Average output voltage
(d) The rms load voltage
(e) The rms load current
(f) DC power
(g) AC power
(h) Rectifier efficiency
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(j) Ripple factor
Chapter 9 Solutions
Delmar's Standard Textbook Of Electricity
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