Chapter 9, Problem 15P

An RLC circuit with an alternating voltage source is shown. The source voltage v, is given by v_s=v_msin(?_dt), where ?_d=2pf_d,in which f_dis the driving frequency. The amplitude of the current, 1, in this circuit is given by:

$I=\frac{v_m}{\sqrt{R^2+{[{\omega }_{d}L-1/({\omega }_{d}C)]}^2}}$

where R and C are the resistance of the resistor and capacitance of the capacitor, respectively. For the circuit in the figure C= 15× 10-⁶F, L=240×10-³H, R=22O, and V_m= 26V. Plot I as a function off for $60\le f\le 110$ Hz. Using MATLAB’s built-in function fminbnd, determine the frequency where I is maximum and the corresponding value of I.