Engineering Economy (17th Edition)
17th Edition
ISBN: 9780134870069
Author: William G. Sullivan, Elin M. Wicks, C. Patrick Koelling
Publisher: PEARSON
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Chapter 9, Problem 15P
To determine
Calculate the present wroth.
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Company X is looking to expand their operations to add a second product line capable of producing 1.25 Million units per year. The total estimated investment cost for the new line is $25 Million, with a salvage value equal to 20% of the purchase price at the end of the 6-year project life. The annual expected sales volume is shown below, in thousands of units: Year 1 2 3 4 5 6Volume 525,000 600,000 725,000 800,000 925,000 1,000,000
The average selling price is fixed for the project life at $125 per unit. Variable costs (per unit) include $35 for materials, $20 for manufacturing, and $18 for labor. There are additional fixed operating and maintenance costs totaling $14.25 Million per year. The company’s working capital calculations are based on a 2.5-month supply of raw materials and 1.5 months of combined inventory (WIP and finished goods) that it maintains to balance overall industry demand. FX…
An engineer calculated the AW values shown for retaining a presently owned
machine additional years.
A challenger has an ESL of 4 years with AW = $-60,000 per year.
Assuming all future costs remain the same, when should the company replace the
defender?
The MARR is 12% per year. Assume used machines like the one presently owned
will always be available.
AW of Defender,
2$
|-77,000
|-63,000
|-58,000
-64,000
-70,000
Years Retained
1
2
3
4
O a) at year 5
O b) at year 4
c) at year 1
d) at year 3
An $80,000 baling machine for recycled paper was purchased by the XYZ company two years ago. The current MV of the machine is $50,000, and it can be kept in service for seven more years. MARR is 12% per year and the projected net annual receipts (revenues less expenses) and end-of-year market values for the machine are shown below. When is the best time for the company to abandon this project?
END OF YEAR
1 2 3 4 5 6 7
Net annual receipts $20,000 $20,000 $18,000 $15,000 $12,000 $6,000 $3,000
Market value 40,000 32,000 25,000 20,000 15,000 10,000 5,000
Chapter 9 Solutions
Engineering Economy (17th Edition)
Ch. 9 - Prob. 1PCh. 9 - Prob. 2PCh. 9 - Prob. 3PCh. 9 - Prob. 4PCh. 9 - Prob. 5PCh. 9 - Prob. 6PCh. 9 - Prob. 7PCh. 9 - A city water and waste-water department has a...Ch. 9 - Prob. 9PCh. 9 - Prob. 10P
Ch. 9 - Prob. 11PCh. 9 - Prob. 12PCh. 9 - Use the PW method to select the better of the...Ch. 9 - Prob. 14PCh. 9 - Prob. 15PCh. 9 - Prob. 16PCh. 9 - Prob. 17PCh. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 20PCh. 9 - Prob. 21PCh. 9 - Prob. 22PCh. 9 - Prob. 23PCh. 9 - Prob. 24PCh. 9 - Prob. 25PCh. 9 - Prob. 26PCh. 9 - Prob. 27SECh. 9 - Prob. 28SECh. 9 - Prob. 29CSCh. 9 - Prob. 30CSCh. 9 - Prob. 31CSCh. 9 - Prob. 32FECh. 9 - Prob. 33FECh. 9 - Prob. 34FECh. 9 - Prob. 35FECh. 9 - Prob. 36FE
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- The replacement of a planning machine is being considered by the Reardon Furniture Company. (There is an indefinite future need for this type of machine.) The best challenger will cost $25,000 for installation and will have an estimated economic life of 14 years and a $1,500 MV at that time. It is estimated that annual expenses will average $16,000 per year. The defender has a present BV of $5,500 and a present MV of $4000. Data for the defender for the next three years are given below. Using a before-tax interest rate of 12% per year, make a comparison to determine whether it is economical to make the replacement now. Year MV at End of BV at End of Expenses during Year 1 $3,000 Year $4,125 the Year $20,000 2 2,750 2,750 26,000 3 2,500 1,375 32,000 Click the icon to view the interest and annuity table for discrete compounding when i = 12% per year. Fill in the table for the EUAC values for the defender for years 1-3. (Round to the nearest dollar.) Year EUAC 1 2 3arrow_forwardAn engineer calculated the AW values shown for retaining a presently owned machine additional years. A challenger has an ESL of 4 years with AW = $-60,000 per year. Assuming all future costs remain the same, when should the company replace the defender? The MARR is 12% per year. Assume used machines like the one presently owned will always be available. AW of Defender, 24 -77,000 -63,000 Years Retained 1 12 -58,000 -64,000 -70,000 13 4 a) at year 5 b) at vear 2 always be available. AW of Defender, 2$ |-77,000 -63,000 -58,000 -64,000 -70,000 Years Retained 3 4 15 O a) at year 5 b) at year 2 c) at year 1 d) at year 4 e) at year 3arrow_forwardA company with a MARR of 10% must install one of two production machines. The economic parameters of each machine are as follows: Machine X Y Initial cost ($) $15,000 $22,000 Service life (years) 4 years 6 years Salvage value end of life ($) $2,000 $1,000 The Future worth (FW) for the machine Y over the 12 years analysis period is:arrow_forward
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