EBK INTRODUCTION TO CHEMISTRY
5th Edition
ISBN: 9781260162165
Author: BAUER
Publisher: MCGRAW HILL BOOK COMPANY
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 9, Problem 126QP
Interpretation Introduction
Interpretation:
The reason why smells take long time to permeate a room is to be determined.
Concept Introduction:
The gas particles move with high average velocity. The particles of gas are loosely packed with each other and store kinetic energy within them. Due to this kinetic energy present in the molecules of gas, the particles have rapid collision between them and the particles of gases travel from one place to another with collisions.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
4. A pressurized gas is allowed to expand. If the gas originally occupied a volume of 420 mL at a pressure of
300. psi, what volume will it occupy if the pressure is lowered to 125 psi?
In the gas law equations, what does the subscript 1 mean and what does the subscript 2 mean?
Explain the following using the concepts of Gas Laws:
What does a scuba diver need to know about gas laws in order to enjoy diving without danger?
Why do deep sea fishes die when brought to the surface?
Why are cases of tire explosion rampant during summer?
Chapter 9 Solutions
EBK INTRODUCTION TO CHEMISTRY
Ch. 9 - Prob. 1QCCh. 9 - Prob. 2QCCh. 9 - Prob. 3QCCh. 9 - Prob. 4QCCh. 9 - Prob. 5QCCh. 9 - Prob. 1PPCh. 9 - Prob. 2PPCh. 9 - What pressure is needed to compress 455 mL of...Ch. 9 - Prob. 4PPCh. 9 - Prob. 5PP
Ch. 9 - Prob. 6PPCh. 9 - Prob. 7PPCh. 9 - Prob. 8PPCh. 9 - Prob. 9PPCh. 9 - Prob. 10PPCh. 9 - Prob. 11PPCh. 9 - Prob. 12PPCh. 9 - Prob. 13PPCh. 9 - Prob. 14PPCh. 9 - Prob. 15PPCh. 9 - Prob. 16PPCh. 9 - Prob. 17PPCh. 9 - Prob. 18PPCh. 9 - Prob. 1QPCh. 9 - Prob. 2QPCh. 9 - Prob. 3QPCh. 9 - Prob. 4QPCh. 9 - A series of organic compounds called the alkanes...Ch. 9 - Prob. 6QPCh. 9 - Prob. 7QPCh. 9 - Prob. 8QPCh. 9 - Prob. 9QPCh. 9 - Prob. 10QPCh. 9 - Prob. 11QPCh. 9 - Prob. 12QPCh. 9 - Prob. 13QPCh. 9 - Prob. 14QPCh. 9 - Prob. 15QPCh. 9 - Prob. 16QPCh. 9 - Prob. 17QPCh. 9 - Prob. 18QPCh. 9 - Prob. 19QPCh. 9 - Prob. 20QPCh. 9 - Prob. 21QPCh. 9 - Prob. 22QPCh. 9 - Prob. 23QPCh. 9 - Prob. 24QPCh. 9 - Prob. 25QPCh. 9 - Prob. 26QPCh. 9 - Prob. 27QPCh. 9 - Prob. 28QPCh. 9 - Prob. 29QPCh. 9 - Prob. 30QPCh. 9 - Prob. 31QPCh. 9 - Prob. 32QPCh. 9 - Prob. 33QPCh. 9 - Prob. 34QPCh. 9 - Prob. 35QPCh. 9 - Prob. 36QPCh. 9 - Prob. 37QPCh. 9 - Prob. 38QPCh. 9 - Prob. 39QPCh. 9 - Prob. 40QPCh. 9 - Prob. 41QPCh. 9 - Prob. 42QPCh. 9 - Prob. 43QPCh. 9 - Prob. 44QPCh. 9 - Prob. 45QPCh. 9 - Prob. 46QPCh. 9 - Prob. 47QPCh. 9 - Prob. 48QPCh. 9 - Prob. 49QPCh. 9 - Prob. 50QPCh. 9 - Prob. 51QPCh. 9 - Prob. 52QPCh. 9 - Prob. 53QPCh. 9 - Prob. 54QPCh. 9 - Prob. 55QPCh. 9 - Prob. 56QPCh. 9 - Prob. 57QPCh. 9 - Prob. 58QPCh. 9 - Prob. 59QPCh. 9 - Prob. 60QPCh. 9 - Prob. 61QPCh. 9 - Prob. 62QPCh. 9 - Prob. 63QPCh. 9 - Prob. 64QPCh. 9 - Prob. 65QPCh. 9 - Prob. 66QPCh. 9 - Prob. 67QPCh. 9 - Prob. 68QPCh. 9 - Prob. 69QPCh. 9 - Prob. 70QPCh. 9 - Prob. 71QPCh. 9 - Prob. 72QPCh. 9 - Prob. 73QPCh. 9 - Prob. 74QPCh. 9 - Prob. 75QPCh. 9 - Prob. 76QPCh. 9 - Prob. 77QPCh. 9 - Prob. 78QPCh. 9 - Prob. 79QPCh. 9 - Prob. 80QPCh. 9 - Prob. 81QPCh. 9 - Prob. 82QPCh. 9 - Prob. 83QPCh. 9 - Prob. 84QPCh. 9 - Prob. 85QPCh. 9 - Prob. 86QPCh. 9 - Prob. 87QPCh. 9 - Prob. 88QPCh. 9 - Prob. 89QPCh. 9 - Prob. 90QPCh. 9 - Prob. 91QPCh. 9 - Prob. 92QPCh. 9 - Prob. 93QPCh. 9 - Prob. 94QPCh. 9 - Prob. 95QPCh. 9 - Prob. 96QPCh. 9 - Prob. 97QPCh. 9 - Prob. 98QPCh. 9 - Prob. 99QPCh. 9 - Prob. 100QPCh. 9 - Prob. 101QPCh. 9 - Prob. 102QPCh. 9 - Prob. 103QPCh. 9 - Prob. 104QPCh. 9 - Prob. 105QPCh. 9 - Prob. 106QPCh. 9 - Prob. 107QPCh. 9 - Prob. 108QPCh. 9 - Prob. 109QPCh. 9 - Prob. 110QPCh. 9 - Prob. 111QPCh. 9 - Prob. 112QPCh. 9 - Prob. 113QPCh. 9 - Prob. 114QPCh. 9 - Prob. 115QPCh. 9 - Prob. 116QPCh. 9 - Prob. 117QPCh. 9 - Prob. 118QPCh. 9 - Prob. 119QPCh. 9 - Prob. 120QPCh. 9 - Prob. 121QPCh. 9 - Prob. 122QPCh. 9 - Prob. 123QPCh. 9 - Prob. 124QPCh. 9 - Prob. 125QPCh. 9 - Prob. 126QPCh. 9 - Prob. 127QPCh. 9 - Prob. 128QPCh. 9 - Prob. 129QPCh. 9 - Prob. 130QPCh. 9 - Prob. 131QPCh. 9 - Prob. 132QPCh. 9 - Prob. 133QPCh. 9 - Prob. 134QPCh. 9 - Prob. 135QPCh. 9 - Prob. 136QPCh. 9 - Prob. 137QPCh. 9 - Prob. 138QPCh. 9 - Prob. 139QPCh. 9 - Prob. 140QPCh. 9 - Prob. 141QPCh. 9 - Prob. 142QPCh. 9 - Prob. 143QPCh. 9 - Prob. 144QPCh. 9 - Prob. 145QPCh. 9 - Prob. 146QPCh. 9 - Prob. 147QPCh. 9 - Prob. 148QPCh. 9 - Prob. 149QPCh. 9 - Prob. 150QPCh. 9 - Prob. 151QPCh. 9 - Prob. 152QPCh. 9 - Prob. 153QPCh. 9 - Prob. 154QPCh. 9 - Prob. 155QPCh. 9 - Prob. 156QPCh. 9 - Prob. 157QPCh. 9 - Prob. 158QPCh. 9 - Prob. 159QPCh. 9 - Prob. 160QPCh. 9 - Prob. 161QPCh. 9 - Prob. 162QPCh. 9 - Prob. 163QPCh. 9 - Prob. 164QPCh. 9 - Prob. 165QPCh. 9 - Butane burns with oxygen according to the...Ch. 9 - Prob. 167QP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- 2. A volume of 0.50 L of air at 37 °C is expelled from the lungs into cold surroundings at 0.0 °C. What volume does the expelled air occupy at this temperature?arrow_forwardapplication of the gas law in the environmentarrow_forward7) An 1.05 mol sample of oxygen gas at a temperature of 27.0 oC is found to occupy a volume of 21.7 liters. Calculate the pressure of this gas sample in atm. 8) A 0.155 mol sample of oxygen gas has a volume of 834 milliliters at a pressure of 4.93 atm. Calculate the temperature of the O2 gas sample on the Celsius scale. 9) A sample of oxygen gas collected at a pressure of 1.05 atm and a temperature of 301 K is found to occupy a volume of 568 milliliters. How many moles of O2 gas are in the sample? 10) Iron nail rusts when exposed to oxygen.4 Fe (s) + 3 O2 (g) 2 Fe2O3 (s) a) What volume of oxygen gas at 31.0 oC and 1.40 atm is required to react completely with 57.3 g of iron according to the above reaction? b) How many grams of iron(III) oxide are produced to from 18.3 L of oxygen gas at 25.0 oC and 1.06 atm according to the above reaction?arrow_forward
- 1. The given volume of H2O2 was 5.00mL. The temperature is 21.4C. ther barometric pressure is 29.79Hg. Suppose the gas that was collected was transferred into another container that had a fixed volume of 85.0 mL. What would be the pressure of the gas inside the second container? A.) At what temperature (in °C) would the gas exert a pressure of 1.55 atm inside the 85.0 mL container?arrow_forwardExplain why volcanoes often erupt violently and relate this to the gas laws?arrow_forwardWhich of the following is true regarding the internal pressure of a gas? A. If the internal pressure is greater than 0, it implies that repulsive forces are dominant and the internal energy of the system increases with volume. B. If the internal pressure is greater than 0, it implies that attractive forces are dominant and the internal energy of the system increases with volume. C. If the internal pressure is less than 0, it implies that attractive forces are dominant and the internal energy of the system increases with volume. D. If the internal pressure is less than 0, it implies that repulsive forces are dominant and the internal energy of the system increases with volume. O E. Internal pressure is 0 for a real gas.arrow_forward
- Explain the gas laws in terms of the Kinetic Molecular Theoryarrow_forward1. The given volume of H2O2 was 5.00mL. The temperature is 21.4C. Suppose the gas that was collected was transferred into another container that had a fixed volume of 85.0 mL. What would be the pressure of the gas inside the second container? A.) At what temperature (in °C) would the gas exert a pressure of 1.55 atm inside the 85.0 mL container?arrow_forward5) Suppose your car is equipped with tire pressure monitoring system (TPMS) and the tire pressure is 34.0 psi on a 98 °F day in California. You decided to take a road trip to Alaska where the temperature drops to 20 °F. As you arrived in Alaska, you noticed that the tire pressure monitoring system alert light is illuminated. Why did this happen? A) as temperature decreases, gas molecules lose kinetic energy and the volume of gas increases thus reducingarrow_forward
- A sample of argon gas at 308 K and 0.985 atm occupies a volume of 3.18 L. If the pressure of the gas is increased, while at the same time it is heated to a higher temperature, the final gas volume could be larger or smaller than 3.18 L depending on the final pressure and temperature. will be larger than 3.18 L. will be smaller than 3.18 L.arrow_forwardA volume of 0.50 L of air at 37 °C is expelled from the lungs into cold surroundings at 0.0 °C. What volume (in L) does the expelled air occupy at this temperature?arrow_forwardWhat does mean free path mean? O It is the average distance traversed by a molecule between collisions with other molecules. O It is the average molecular diameter in a gas. O It is the number density of the molecules (the number per unit volume). O It is the inverse of the number density of the molecules (the number per unit volume).arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning