
a.
To find: the parametric equations that represent the path of probes.
a.

Answer to Problem 8CFU
x=440ty=−16t2+3500
Explanation of Solution
Given information:
Height (h)=3500 feet
Initial velocity (→v)=330 mph
Path of plane is parallel to the ground at the time of releasing the probes, so θ=0° .
Calculation:
First convert the velocity into feet per second as follows:
|→v|=330 mph(5280 feet1 mile)(1 hour3600 s)=440 feet per second
Now solve the horizontal and vertical components as shown below.
x=t|→v|cosθ=t(440)cos0° [Put the value of |→v| and θ]=440t
y=t|→v|sinθ−12gt2+h=t(440)sin0°−12(32)t2+3500 [Put the value of |→v|,g,h and θ]=−16t2+3500
Thus the parametric equations are x=440t and y=−16t2+3500 .
b.
To graph: the parametric equations that represent the path of probes.
b.

Explanation of Solution
Given information:
Parametric equations evaluated in part a. are shown below.
x=440ty=−16t2+3500
Calculation:
Express t in terms of x as shown below.
x=440tt=x400
Now substitute the value of t in parametric equation for y as follows:
y=−16t2+3500=−16(x400)2+3500
Create a table of values for x and y as shown below.
x | 0 | 1000 | 2000 | 3000 | 4000 | 5000 | 6000 | 6507 |
y | 3500 | 3417.3 | 3169.4 | 2756.2 | 2177.7 | 1433.8 | 524.8 | 0.7 |
Plot the points and join them with a soft curve to get the graph of given parametric equations as shown below.
c.
To find: the time taken by the probes to reach the ground.
c.

Answer to Problem 8CFU
14.8 seconds
Explanation of Solution
Given information:
Parametric equations evaluated in part a. are shown below.
x=440ty=−16t2+3500
Calculation:
When the probe will reach the ground the value of y will become zero. Substitute y=0 in the equation for y and solve t as shown below.
y=−16t2+35000=−16t2+3500 [Put y=0]16t2=3500 [Add 16t2 on each side]t2=350016 [Divide each side by 16]t=√350016 [Taking square roots on each side]=14.8 seconds
Thus the required time taken by probe to reach the ground is 14.8 seconds.
d.
To find: the horizontal distance travelled by probes before hitting the ground.
d.

Answer to Problem 8CFU
6214 feet
Explanation of Solution
Given information:
Parametric equations evaluated in part a. are shown below.
x=440ty=−16t2+3500
Time taken to reach the ground (t)=14.8 seconds
Calculation:
Substitute the value of t in parametric equation for x and solve as follows:
x=440t=440(14.8)=6214 feet
Thus the horizontal distance travelled by probes before hitting the ground is 6215 feet.
Chapter 8 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
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