Chapter 8.6, Problem 60PPS

To determine

To find: The value of given equation.

Answer to Problem 60PPS

The value of given equation is $x\approx \pm 1.3335$ .

Explanation of Solution

Given information:

The equation is ${10}^{x^2}=60$ .

Calculation:

Consider the expression.

  $\begin{array}{l}{10}^{x^2}=60\\ \log {10}^{x^2}=\log 60\\ x^2=\frac{\log 60}{\log 10}\\ x^2=\log 60\\ x=\pm \sqrt{\log 60}\\ x\approx \pm 1.3335\end{array}$