Chapter 8.4, Problem 27E

(a)

To determine

To find: The area of $EFGH\&EJKL$ .

Answer to Problem 27E

The areas of $EFGH\&EJKL$ are $4$ and $16$ respectively.

Explanation of Solution

Given information: The following figure is been given:

  

Formula used: $A=b\times h$

Calculation: The area of the square $EFGH$

  $\begin{array}{l}A=2\times 2\\ \therefore A=4\end{array}$

The area of the square $EJKL$

  $\begin{array}{l}A=4\times 4\\ \therefore A=16\end{array}$

If the perimeter becomes double, then the original square is quadrupled.

(b)

To determine

To explain: Whether the given situation is true for every square or not.

Answer to Problem 27E

Yes, it is true.

Explanation of Solution

Given information: The following figure is been given:

  

Formula used: $A=b\times h$

Calculation: If the perimeter becomes double, then the original square is quadrupled.

  $\therefore A=2s^2=4s^2$