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In Problems 1–8 use the method of undetermined coefficients to solve the given nonhomogeneous system.
3.
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A First Course in Differential Equations with Modeling Applications (MindTap Course List)
- 6. (2x +3y = 0 /2x x+2y =-1 9. (1 1 -X+-y 5 1, -x+y%3D10 4arrow_forwardExample 1.21 y" + 5y" + 12y' + 8y = 5sin2x + 10x? - 3x + 7 private solution yo =?arrow_forward1. Find the solution to the initial value problem 4x3 + 1 2у — 6 y(1) = 2. A. y = 3 – Vxª + x – 1 B. y = 2+ Vx³ + x – 2 C. y = 1+ Vx4 + x – 1 D. y = 4 – V4x³ + x – 1 E. y = V4³ + x – 1arrow_forward
- 9. discuss the behavior of the dynamical system Xk+1= Axk where -0.31 (@) A = [ (b) A = ["0.3 11 1.5 0.3 (b) A = 0.3 1 3Darrow_forwardProblem 16 (#2.3.34).Let f(x) = ax +b, and g(x) = cx +d. Find a condition on the constants a, b, c, d such that f◦g=g◦f. Proof. By definition, f◦g(x) = a(cx +d) + b=acx +ad +b, and g◦f(x) = c(ax +b) + d=acx +bc +d. Setting the two equal, we see acx +ad +b=acx +bc +d ad +b=bc +d (a−1)d=(c−1)b That last step was merely added for aesthetic reasons.arrow_forwardUse (1) in Section 8.4 X = eAtc (1) to find the general solution of the given system. 1 X' = 0. X(t) =arrow_forward
- Q.3// Use Tow Phase method to solve the Mathematical model (Stop at Table 1 in Stage Two) Max Z = X1 + 3xz+ 4x3+ 5 S.t. 4x1+ 3x3+ 2x3+x40arrow_forward3. Solve the following using Two Phase Method MIN Z = x1 + x2 subject to 2x1 + x2 >= 4 x1 + 7x2 >= 7 and x1,x2 >= 0arrow_forwardProblem 2. Consider the equation: x?y"(x) – xy' +y = 0. Given that yı(x) = x is a solution of this equation. Use the method of reduction of order, find the second solution y2(x) of the equation so that y1 and y2 are linearly independent. (Hint: y2(x) should be given in the form y2(x) = u(x)y1(x). Substitute it into the equation to find u(x).) %3Darrow_forward
- 2. Find the general solution of this system. -1 1 x' = -1 1 1 -1 -1arrow_forward11. What is the general solution of* (2x – y)dx + (4x + y - 6)dy = 0 (2 +y – 3) = c(2x + y - 4)2 (x – y + 3)? = c(2æ + y – 4)3 Option 1 Option 2 (2 - y - 3) = c(2r - y- 4) (x+y - 3) = c(x + 2y – 4)?arrow_forward10. Find the general solution of the system of differential equations 3 -2 -2 d. X = -3 -2 -6 X dt 3 10 1 + 2tet + 3t?et + 4t°et 3 1 -3 Hint: The characteristic polymomial of the coefficient matrix is -(A- 4)²(A- 3). Moreover (:) 2 1 Xp(t) = t²et +t³et +t'e3t -1 -1 -3 is a particular solution of the system.arrow_forward
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