Chapter 8.3, Problem 25PPS

To determine

To find: The product $\left(2y-11\right)\left(y^2-3y+2\right)$

Answer to Problem 25PPS

  $2y^3-17y^2+37y-22$

Explanation of Solution

Given:

  $\left(2y-11\right)\left(y^2-3y+2\right)$

Calculation:

Multiply each term of the first polynomial with the each term of the second polynomial

  $\begin{array}{l}\left(2y-11\right)\left(y^2-3y+2\right)\\ =2y\cdot y^2+2y\cdot \left(-3y\right)+2y\cdot 2-11\cdot y^2-11\cdot \left(-3y\right)-11\cdot 2\\ =2y^3-6y^2+4y-11y^2+33y-22\\ =2y^3-17y^2+37y-22\end{array}$

So, the product of the polynomial is $2y^3-17y^2+37y-22$