Chapter 8.3, Problem 10MCQ

To determine

To simplify: the expression

Answer to Problem 10MCQ

The value of the expression $\frac{2}{4x^{2}y}+\frac{x}{3x{y}^3}$ is $\frac{6x{y}^2+4x^2}{12x^2{y}^3}$

Explanation of Solution

Given information: The expression is $\frac{2}{4x^{2}y}+\frac{x}{3x{y}^3}$

Calculation:

From the expression $\frac{2}{4x^{2}y}+\frac{x}{3x{y}^3}$

Take LCM of the both denominator

LCM $=12x^2{y}^3$

  $\frac{2x}{4x^{2}y}\times \frac{3y^2}{3y^2}+\frac{x}{3x{y}^3}\times \frac{4x}{4x}$

Multiply the denominator and numerator by the values that will make the denominator

  $\frac{6x{y}^2+4x^2}{12x^2{y}^3}$