Explanation Given: The total income from these investments is $ 716 and the total amount of money invested at 12% is $300 more than the amount invested at 8% and 10% combined.. Calculation: Let the part of amount invested at 8% is x , the part of amount invested at 10% is y, and the part of amount invested at 12% is z . The three statements are as follows: (1) Total amount to be invested is $6700. It implies x + y + z = 6700 (2)Total income derived from all of these investments is $716. It implies 0.08 x + 0.10 y + 0.12 z = 716 8 x + 10 y + 12 z = 71 , 600 (3) The total amount of money invested at 12% is $300 more than the amount invested at 8% and 10% combined. It implies z = 300 + x + y z − x − y = 300 Mark the system of equation as follows: x + y + z = 6700 (I) 8 x + 10 y + 12 z = 71 , 600 (II) z − x − y = 300 (III) Add equations (I) and (III) to get the value of z, x + y + z = 6700 − x − y + z = 300 _ 2 z = 7000 (IV) Divide both sides by 2 to get, 2 z 2 = 7000 2 z=3500 Multiply equation (I) by –10 and eliminate y equations (I) and (II) to get, 8 x + 10 y + 12 z =

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ISBN: 9780136922179

Author: Blitzer

Publisher: RENT PEARS

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Chapter 8.2, Problem 39E

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To calculate: The part of amount invested at 8%, that is, x, the part of amount invested at 10% that is y, and the part of amount invested at 12% that is z.

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Chapter 8.2, Problem 38E

Chapter 8.2, Problem 40E

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The part of amount invested at 8%, that is, x , the part of amount invested at 10% that is y, and the part of amount invested at 12% that is z .

Solution Summary: The author calculates the part of amount invested at 8%, x, 10%, and 12%. The total income derived from all of these investments is 716.

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To calculate: The part of amount invested at 8%, that is, x, the part of amount invested at 10% that is y, and the part of amount invested at 12% that is z.

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Chapter 8 Solutions