Chapter 8.1, Problem 39WE

To determine

To find: The number of chicken and the pigs bought.

Answer to Problem 39WE

The different number of chicken and the pigs bought is shown in Table 1

Explanation of Solution

Given:

The cost of each pig is $\$40$

The cost of each chicken is $\$3$

The total cost is $\$280$ .

Calculation:

Consider the cost of pig is $x$ and the cost of chicken is $y$ , then,

  $\begin{array}{l}40x+3y=280\\ y=\frac{-40x+280}{3}\end{array}$

The number of pigs and chicken is shown in Table 1

Table 1

$x$	$y=\frac{-40x+280}{3}$
$1$	$\begin{array}{c}y=\frac{-40\left(1\right)+280}{3}\\ =80\end{array}$
$2$	$\begin{array}{c}y=\frac{-40\left(2\right)+280}{3}\\ =\frac{200}{3}\end{array}$
$3$	$\begin{array}{c}y=\frac{-40\left(3\right)+280}{3}\\ =\frac{160}{3}\end{array}$