(a)
Interpretation:
The number of moles of solute required to prepare of
Concept introduction:
Several concentration units may be used to express the concentration. It is often useful to express the concentration in terms of percentage. This can be expressed as the amount of solute in grams dissolved in
The formula to calculate molarity is given as follows:
(b)
Interpretation:
The number of moles of
Concept introduction:
Several concentration units may be used to express the concentration. It is often useful to express the concentration in terms of percentage. This can be expressed as the amount of solute in grams dissolved in
The formula to calculate molarity is given as follows:
(c)
Interpretation:
The number of moles of
Concept introduction:
Several concentration units may be used to express the concentration. It is often useful to express the concentration in terms of percentage. This can be expressed as the amount of solute in grams dissolved in
The formula to calculate molarity is given as follows:
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Chapter 8 Solutions
General, Organic, & Biological Chemistry
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- 34. For each of the following solutions, the number of moles of solute is given, followed by the total volume of the solution prepared. Calculate the molarity of each solution. a. 0.754 mol KNO; 225 mL b. 0.0105 in of CaCl; 10.2 mL c. 3.15 mol NaCl; 5.00 L d. 0.499 mol NaBr; 100. mLarrow_forwardConsider a 13.0% solution of sulfuric acid, H2SO4,whose density is 1.090 g/mL. (a) Calculate the molarity of this solution. (b) To what volume should 100. mL of this solution bediluted to prepare a 1.10-M solution?arrow_forward3.65 Determine the final molarity for the following dilutions. (a) 24.5 mL of 3.0 M solution diluted to 100.0 mL (b) 15.3 mL of 4.22 M solution diluted to 1.00 L (c) 1.45 mL of 0.034 M solution diluted to 10.0 mL (d) 2.35 L of 12.5 M solution diluted to 100.0 Larrow_forward
- 3.61 Calculate the molarity of each of the following solutions. (a) 1.45 mol HCl in 250. mL of solution (b) 14.3 mol NaOH in 3.4 L of solution (c) 0.341 mol KCl in 100.0 mL of solution (d) 250 mol NaNO3 in 350 L of solutionarrow_forwardWhat volume of 0.250 M HCI is required to neutralize each of the following solutions? a. 25.0 mL of 0.103 M sodium hydroxide, NaOH b. 50.0 mL of 0.00501 M calcium hydroxide, Ca(OH)2 c. 20.0 mL of 0.226 M ammonia, NH3 d. 15.0 mL of 0.0991 M potassium hydroxide, KOHarrow_forwardCalcium carbonate, CaCO3, can be obtained in a very pure state. Standard solutions of calcium ion are usually prepared by dissolving calcium carbonate in acid. What mass of CaCO3 should be taken to prepare 500. mL of 0.0200 M calcium ion solution?arrow_forward
- Calculate the molarity of each of the following solutions: (a) 0.195 g of cholesterol, C27H46O, in 0.100 L of serum, the average concentration of cholesterol in human serum (b) 4.25 g of NH3 in 0.500 L of solution, the concentration of NH3 in household ammonia (c) 1.49 kg of isopropyl alcohol, C3H7OH, in 2.50 L of solution, the concentration of isopropyl alcohol in rubbing alcohol (d) 0.029 g of I2 in 0.100 L of solution, the solubility of I2 in water at 20 Carrow_forwardA student weighs out a 4.80-g sample of aluminum bromide, transfers it to a 100-mL volumetric flask, adds enough water to dissolve it, and then adds water to the 100-mL mark. What is the molarity of aluminum bromide in the resulting solution?arrow_forward
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