Loose Leaf for Chemistry: The Molecular Nature of Matter and Change
Loose Leaf for Chemistry: The Molecular Nature of Matter and Change
8th Edition
ISBN: 9781260151749
Author: Silberberg Dr., Martin; Amateis Professor, Patricia
Publisher: McGraw-Hill Education
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Chapter 8, Problem 8.76P

(a)

Interpretation Introduction

Interpretation:

The charge and full ground state electron configuration of the ion likely to be formed by Rb is to be determined.

Concept introduction:

The electronic configuration of an atom describes how the electrons are ditributed in its atom among various shells and subshells. It is used to predict the chemical, physical, electrical and magnetic properties of the substance. The full electronic configuration of an atom tells about the distribution of electrons in the various atomic orbitals.

(a)

Expert Solution
Check Mark

Answer to Problem 8.76P

The charge of monoatomic ion likely to be formed by Rb atom is +1.

The full ground state electron configuration of the ion likely to be formed by Rb is 1s22s22p63s23p64s23d104p6.

Explanation of Solution

The atomic number of rubidium is 37 so its ground state electronic configuration is 1s22s22p63s23p64s23d104p65s1. Its configuration is just one electron more of the stable noble gas configuration of krypton so it loses one electron to become Rb+ whose full ground state electron configuration is 1s22s22p63s23p64s23d104p6.

The ion formation occurs as follows:

Rb(1s22s22p63s23p64s23d104p65s1)eRb+(1s22s22p63s23p64s23d104p6)

So the charge on the ion formed by Rb is +1 and its full ground state electron configuration is 1s22s22p63s23p64s23d104p6.

Conclusion

The charge of monoatomic ion likely to be formed by Rb atom is +1 and the full ground state electron configuration of the ion likely to be formed by Rb is 1s22s22p63s23p64s23d104p6.

(b)

Interpretation Introduction

Interpretation:

The charge and full ground state electron configuration of the ion likely to be formed by N is to be determined.

Concept introduction:

The electronic configuration of an atom describes how the electrons are ditributed in its atom among various shells and subshells. It is used to predict the chemical, physical, electrical and magnetic properties of the substance. The full electronic configuration of an atom tells about the distribution of electrons in the various atomic orbitals.

(b)

Expert Solution
Check Mark

Answer to Problem 8.76P

The charge of monoatomic ion likely to be formed by N atom is -3.

The full ground state electron configuration of the ion likely to be formed by N is 1s22s22p6.

Explanation of Solution

The atomic number of nitrogen is 7 so its ground state electronic configuration is 1s22s22p3. Its configuration is just three electrons short of the stable noble gas configuration of neon so it gains three electrons to become N3 whose full ground state electron configuration is 1s22s22p6.

The ion formation occurs as follows:

N(1s22s22p3)+3eN3(1s22s22p6)

So the charge on the ion formed by N is -3 and its full ground state electron configuration is 1s22s22p6.

Conclusion

The charge of monoatomic ion likely to be formed by N atom is -3 and the full ground state electron configuration of the ion likely to be formed by N is 1s22s22p6.

(c)

Interpretation Introduction

Interpretation:

The charge and full ground state electron configuration of the ion likely to be formed by Br is to be determined.

Concept introduction:

The electronic configuration of an atom describes how the electrons are ditributed in its atom among various shells and subshells. It is used to predict the chemical, physical, electrical and magnetic properties of the substance. The full electronic configuration of an atom tells about the distribution of electrons in the various atomic orbitals.

(c)

Expert Solution
Check Mark

Answer to Problem 8.76P

The charge of monoatomic ion likely to be formed by Br atom is -1.

The full ground state electron configuration of the ion likely to be formed by Br is 1s22s22p63s23p64s23d104p6.

Explanation of Solution

The atomic number of bromine is 35 so its ground state electronic configuration is 1s22s22p63s23p64s23d104p5 Its configuration is one electron short of the stable noble gas configuration of krypton so it gains one electron to become Br whose full ground state electron configuration is 1s22s22p63s23p64s23d104p6.

The ion formation occurs as follows:

Br(1s22s22p63s23p64s23d104p5)+eBr(1s22s22p63s23p64s23d104p6)

So the charge on the ion formed by Br is -1 and its full ground state electron configuration is 1s22s22p63s23p64s23d104p6.

Conclusion

The charge of monoatomic ion likely to be formed by Br atom is -1 and the full ground state electron configuration of the ion likely to be formed by Br is 1s22s22p63s23p64s23d104p6.

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Chapter 8 Solutions

Loose Leaf for Chemistry: The Molecular Nature of Matter and Change

Ch. 8.4 - Prob. 8.6AFPCh. 8.4 - Prob. 8.6BFPCh. 8.4 - Prob. 8.7AFPCh. 8.4 - Prob. 8.7BFPCh. 8.4 - Prob. 8.8AFPCh. 8.4 - Prob. 8.8BFPCh. 8 - Prob. 8.1PCh. 8 - Prob. 8.2PCh. 8 - Prob. 8.3PCh. 8 - To test Döbereiner’s idea (Problem 8.3),...Ch. 8 - Summarize the rules for the allowable values of...Ch. 8 - Prob. 8.6PCh. 8 - State the exclusion principle. What does it imply...Ch. 8 - What is the key distinction between sublevel...Ch. 8 - Prob. 8.9PCh. 8 - Prob. 8.10PCh. 8 - Prob. 8.11PCh. 8 - How many electrons in an atom can have each of the...Ch. 8 - Prob. 8.13PCh. 8 - How many electrons in an atom can have each of the...Ch. 8 - Prob. 8.15PCh. 8 - State Hund’s rule in your own words, and show its...Ch. 8 - Prob. 8.17PCh. 8 - For main-group elements, are outer electron...Ch. 8 - Prob. 8.19PCh. 8 - Prob. 8.20PCh. 8 - Prob. 8.21PCh. 8 - Prob. 8.22PCh. 8 - Write the full ground-state electron configuration...Ch. 8 - Prob. 8.24PCh. 8 - Prob. 8.25PCh. 8 - Prob. 8.26PCh. 8 - Prob. 8.27PCh. 8 - Draw a partial (valence-level) orbital diagram,...Ch. 8 - Prob. 8.29PCh. 8 - Draw a partial (valence-level) orbital diagram,...Ch. 8 - Draw the partial (valence-level) orbital diagram,...Ch. 8 - Prob. 8.32PCh. 8 - Prob. 8.33PCh. 8 - Prob. 8.34PCh. 8 - Prob. 8.35PCh. 8 - Prob. 8.36PCh. 8 - How many inner, outer, and valence electrons are...Ch. 8 - How many inner, outer, and valence electrons are...Ch. 8 - Prob. 8.39PCh. 8 - Prob. 8.40PCh. 8 - Prob. 8.41PCh. 8 - Prob. 8.42PCh. 8 - Prob. 8.43PCh. 8 - Prob. 8.44PCh. 8 - If the exact outer limit of an isolated atom...Ch. 8 - Given the following partial (valence-level)...Ch. 8 - In what region of the periodic table will you find...Ch. 8 - Why do successive IEs of a given element always...Ch. 8 - Prob. 8.49PCh. 8 - Prob. 8.50PCh. 8 - Prob. 8.51PCh. 8 - Prob. 8.52PCh. 8 - Prob. 8.53PCh. 8 - Prob. 8.54PCh. 8 - Prob. 8.55PCh. 8 - Prob. 8.56PCh. 8 - Prob. 8.57PCh. 8 - Prob. 8.58PCh. 8 - Prob. 8.59PCh. 8 - Prob. 8.60PCh. 8 - Prob. 8.61PCh. 8 - Prob. 8.62PCh. 8 - Prob. 8.63PCh. 8 - Prob. 8.64PCh. 8 - Prob. 8.65PCh. 8 - What is a pseudo-noble gas configuration? Give an...Ch. 8 - How are measurements of paramagnetism used to...Ch. 8 - Prob. 8.68PCh. 8 - Prob. 8.69PCh. 8 - Prob. 8.70PCh. 8 - Prob. 8.71PCh. 8 - Prob. 8.72PCh. 8 - Prob. 8.73PCh. 8 - Prob. 8.74PCh. 8 - Prob. 8.75PCh. 8 - Prob. 8.76PCh. 8 - Prob. 8.77PCh. 8 - Prob. 8.78PCh. 8 - Prob. 8.79PCh. 8 - Prob. 8.80PCh. 8 - Which of these atoms are paramagnetic in their...Ch. 8 - Prob. 8.82PCh. 8 - Prob. 8.83PCh. 8 - Write the condensed ground-state electron...Ch. 8 - Prob. 8.85PCh. 8 - Prob. 8.86PCh. 8 - Rank the ions in each set in order of increasing...Ch. 8 - Prob. 8.88PCh. 8 - Prob. 8.89PCh. 8 - Prob. 8.90PCh. 8 - Prob. 8.91PCh. 8 - A fundamental relationship of electrostatics...Ch. 8 - Prob. 8.93PCh. 8 - Prob. 8.94PCh. 8 - Prob. 8.95PCh. 8 - Prob. 8.96PCh. 8 - Prob. 8.97PCh. 8 - Prob. 8.98PCh. 8 - Use Figure 8.16, to find: (a) the longest...Ch. 8 - Prob. 8.100PCh. 8 - Prob. 8.101PCh. 8 - Prob. 8.102P
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