Fundamentals of Aerodynamics
Fundamentals of Aerodynamics
6th Edition
ISBN: 9781259129919
Author: John D. Anderson Jr.
Publisher: McGraw-Hill Education
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Chapter 8, Problem 8.3P

At a given point in a flow, T = 300 K , p = 1.2 atm , and V = 250 m/s . At this point, calculate the corresponding values of p 0 , T 0 , p * , T * , and M * .

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At a given point in a flow, T = 300 K, p = 1.2 atm, and V = 250 m/s. Atthis point, calculate the corresponding values of p0, T0, p∗, T ∗, and M∗.
R₂ = 20 mm Flow- Liquid p= 1000 kg/m³ μ = 0.02 Pa s Ri. A Ro A liquid flows through the space between a small rod and a pipe, as shown in diagram below. The outer radius of the pipe is R₁, the inner radius of the rod is R₁, and the ratio λ pressure difference per unit length (Ap/L) of 2000 Pa/m is applied to drive the fluid flow. The liquid has a viscosity of μ = 0.02 Pa's. Q = π If the equation of volumetric flow rate (Q) of the liquid, is given as ApR" ApR" (Ri 8μ L 8μ L + -20% 4 R R₁ = AR₁ = 10 mm + Ro Ri (A) What should be the value of "n", for the equation above to be dimensionally consistent? Use dimensional analysis. n (1-2²)² ApR" 8μ L In ==. (B) Calculate the value of volumetric flow rate in cubic meter per second when r = (Ro+ R₁)/2, and Ro = 20mm, R₁ = 10mm. Report your result with three significant figures.
The velocity profile of a liquid flows through the z direction of the vertical tube (figure right) with the radius ro is given as; r 1 dp Vz = (r² – r3) 2µ dz Specify the maximum velocity and derive an expression for the average velocity.
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