EBK EXPLORING CHEMICAL ANALYSIS
EBK EXPLORING CHEMICAL ANALYSIS
5th Edition
ISBN: 8220101443908
Author: Harris
Publisher: MAC HIGHER
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Chapter 8, Problem 8.31P
Interpretation Introduction

Interpretation:

The value of pH and fraction of association of 0.026MNaOCl has to be found.

Concept Introduction:

pH:

pH is a scale used to specify how acidic or basic a solution is.  It ranges from 0-14. pH 7.0 is considered as neutral solution, pH more than 7.00 is taken as basic solution whereas pH less than 7.0 is considered as acidic solution (at 25oC).  It is the measurement of activity of free H+ and OH- in solution.

  pH=log[H3O+]

  pOH=log[OH]

From ionization constant of water Kw=[H+][OH-]

Ionization constant of water at 25οC Kw=1×1014.

Less the pH more is the acidity of the solution.

Expert Solution & Answer
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Explanation of Solution

The equation as follows,

  OCl(aq)+H2O(l)HOCl(aq)+OH(aq)

As known, Kb=[HOCl][OH][OCl]

Dissociation of acid as shown below,

  HOCl(aq)H+(aq)+OCl(aq)

The value of Ka as,

    3.5×10-8=[OCl][H+][HOCl]

The value of Kb is calculated as,

  Kb=KwKa=1×10-143.5×10-8=2.86×10-7

For the reaction,

  OCl-(aq)+H2O(l)HOCl (aq)+OH-(aq)(0.00573-x)xx

From the above equation,

  Kb=[HOCl][OH-][OCl-]2.86×10-7=x20.00573xAs'x'isnegligible,x=(2.86×10-7)(0.00573)=0.01639×10-7=4.05×10-5.

Fraction of association of base:

  [BH+][BH+]+[B]=4.05×10-5(4.05×10-5)+0.00573=4.05×10-55.7705×10-3=0.0070

The fraction of association is 0.0070.

The value of pOH is calculated as,

  pOH=log[OH-]=log(4.05×10-5)=4.39.pH=14pOH=144.39=9.6

Therefore, the value of pH is 9.6.

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