Concept explainers
(a)
Prove that the electron beam must be ejected out of the field in parallel path to the input beam as mentioned in the Figure given in the textbook.
(a)
Explanation of Solution
Calculation:
Refer to the mentioned Figure given in the textbook.
Consider the general expression to calculate the force using Newton’s second law of motion.
Here,
Rewrite the equation (1) as follows,
Reduce the equation as follows,
From equation (2), the velocities are,
From equation (3),
On solving the above expression,
From equation (3),
Reduce the equation as follows,
Substitute 0 for t in equation (6) and (7).
Therefore, equation (6) and (7) becomes,
At
From equation (10) and (11),
From the above expression, the electron must move in a circle which is centered at
Conclusion:
Thus, the electron beam must be ejected out of the field in parallel path to the input beam is proved.
(b)
Find an expression for the exit distance (d) above the entry point as shown in the mentioned Figure given in the textbook.
(b)
Answer to Problem 6P
The exit distance (d) above the entry point is
Explanation of Solution
Calculation:
Refer to the mentioned Figure given in the textbook. The distance d is twice the radius of the semi-circle. Therefore,
Conclusion:
Thus, the exit distance (d) above the entry point is
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Chapter 8 Solutions
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