A constant torque of 24.5 N · m is applied to a grindstone whose moment of inertia is 0.130 kg · m2. Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 14.0 revolutions. Hint: the angular equivalent ofWnet = FΔx = 12mvf2 − 12mvi2isWnet = τΔ? = 12Iωf2 − 12Iωi2.You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.) rev/s A constant torque of 24.5 N • m is applied to a grindstone whose moment of inertia is 0.130 kg · m². Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 14.0 revolutions. Hint: the= FAx = mv? -mv,? is W,2angular equivalent of W,= tA0 =2You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.)netnet222rev/sеВook

Given data: The constant torque applied to the grindstone is T=24.5 N⋅m. The moment of inertia of…

Answered: A constant torque of 24.5 N. m is…

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter7: Energy Of A System

Section: Chapter Questions

Problem 15P: A small particle of mass m is pulled to the top of a friction less half-cylinder (of radius R) by a...

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A constant torque of 24.5 N · m is applied to a grindstone whose moment of inertia is 0.130 kg · m². Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 14.0 revolutions. Hint: the angular equivalent of

W_net = FΔx =

mv_f² −

mv_i²

W_net = τΔ? =

Iω_f² −

Iω_i².

You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.)
rev/s

A constant torque of 24.5 N • m is applied to a grindstone whose moment of inertia is 0.130 kg · m². Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 14.0 revolutions. Hint: the
= FAx = mv? -mv,? is W,
2
angular equivalent of W,
= tA0 =
2
You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.)
net
net
2
2
2
rev/s
еВook

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