Principles of Information Systems (MindTap Course List)
12th Edition
ISBN: 9781285867168
Author: Ralph Stair, George Reynolds
Publisher: Cengage Learning
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Chapter 8, Problem 3PSE
Explanation of Solution
Peer input to validate the choice:
- The user want to buy “Top Mount refrigerator”.
- The height of the refrigerator will be between “17 cubic foot” and “20 cubic foot”.
- The price of the refrigerator should be below $1000.
Table to perform price and product comparison:
The user visit the website “The Home Depot” to give brief comparative analysis of 6 models of Top Mount refrigerator based on the given input.
| Manufacturer | Model Number | Description | Price | Delivery |
| Hotpoint | HPS18BTHWW | 17.6 cubic foot top freezer refrigerator in white. | $549 | Free |
| Whirlpool | WRT549SZDW | 19.2 cubic foot top freezer refrigerator in white. | $799 | Free |
| Frigidaire | FFTR1821QW | 18 cubic foot top freezer refrigerator in white. | $565 | Free |
| General Electric (GE) | GIE18HSHSS | 17.5 cubic foot top freezer refrigerator in stainless steel. | $899 | Free |
| Amana | ART318FFDS | 18.15 cubic foot top freezer refrigerator in white. | $719 | Free |
| General Electric (GE) | GTS18GTHWW | 17... |
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Consider the following scenario in which host 10.0.0.1 is communicating with an external SMTP mail server at IP
address 128.119.40.186.
NAT translation table
WAN side addr
LAN side addr
(c), 5051
(d), 3031
S: (e),5051
SMTP
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D (f.(g)
10.0.0.4
server
138.76.29.7
128.119.40.186
(a) is the source IP address at A, and its value.
S: (a),3031
D: (b), 25
10.0.0.1
A
10.0.0.2.
1. 138.76.29.7
10.0.0.3
6.3A-3. Multiple Access protocols (3). Consider the figure below, which shows the arrival of 6
messages for transmission at different multiple access wireless nodes at times t=0.1, 1.4, 1.8, 3.2,
3.3, 4.1. Each transmission requires exactly one time unit.
1
t=0.0
2
3
45
t=1.0
t-2.0
t-3.0
6
t=4.0
t-5.0
For the CSMA protocol (without collision detection), indicate which packets are successfully
transmitted. You should assume that it takes .2 time units for a signal to propagate from one node to
each of the other nodes. You can assume that if a packet experiences a collision or senses the
channel busy, then that node will not attempt a retransmission of that packet until sometime after
t=5. Hint: consider propagation times carefully here. (Note: You can find more examples of problems similar to this here B.]
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Just wanted to know, if you had a scene graph, how do you get multiple components from a specific scene node within a scene graph? Like if I wanted to get a component from wheel from the scene graph, does that require traversing still?
Like if a physics component requires a transform component and these two component are part of the same scene node. How does the physics component knows how to get the scene object's transform it is attached to, this being in a scene graph?
Chapter 8 Solutions
Principles of Information Systems (MindTap Course List)
Ch. 8.3 - Prob. 1DQCh. 8.3 - Prob. 2DQCh. 8.3 - Prob. 1CTQCh. 8.3 - Prob. 2CTQCh. 8.5 - Prob. 1DQCh. 8.5 - Prob. 2DQCh. 8.5 - Prob. 1CTQCh. 8.5 - Prob. 2CTQCh. 8 - Prob. 1SATCh. 8 - Prob. 2SAT
Ch. 8 - Prob. 3SATCh. 8 - Prob. 4SATCh. 8 - Prob. 5SATCh. 8 - Prob. 6SATCh. 8 - Prob. 7SATCh. 8 - Prob. 8SATCh. 8 - Prob. 9SATCh. 8 - Prob. 10SATCh. 8 - Prob. 11SATCh. 8 - Prob. 12SATCh. 8 - Prob. 13SATCh. 8 - Prob. 14SATCh. 8 - Prob. 15SATCh. 8 - Prob. 16SATCh. 8 - Prob. 17SATCh. 8 - Prob. 1RQCh. 8 - Prob. 2RQCh. 8 - Prob. 3RQCh. 8 - Prob. 4RQCh. 8 - Prob. 5RQCh. 8 - Prob. 6RQCh. 8 - Prob. 7RQCh. 8 - Prob. 8RQCh. 8 - Prob. 9RQCh. 8 - Prob. 10RQCh. 8 - Prob. 11RQCh. 8 - Prob. 12RQCh. 8 - Prob. 13RQCh. 8 - Prob. 14RQCh. 8 - Prob. 1DQCh. 8 - Prob. 2DQCh. 8 - Prob. 3DQCh. 8 - Prob. 4DQCh. 8 - Prob. 5DQCh. 8 - Prob. 6DQCh. 8 - Prob. 7DQCh. 8 - Prob. 8DQCh. 8 - Prob. 9DQCh. 8 - Prob. 10DQCh. 8 - Prob. 11DQCh. 8 - Prob. 12DQCh. 8 - Prob. 1PSECh. 8 - Prob. 3PSECh. 8 - Prob. 1TACh. 8 - Prob. 2TACh. 8 - Prob. 2WECh. 8 - Prob. 1CECh. 8 - Prob. 2CECh. 8 - Prob. 1DQ1Ch. 8 - Prob. 2DQ1Ch. 8 - Prob. 1CTQ1Ch. 8 - Prob. 2CTQ1Ch. 8 - Prob. 1DQ2Ch. 8 - Prob. 2DQ2Ch. 8 - Prob. 1CTQ2Ch. 8 - Prob. 2CTQ2Ch. 8 - Prob. 1DQ3Ch. 8 - Prob. 2DQ3Ch. 8 - Prob. 1CTQ3Ch. 8 - Prob. 2CTQ3
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