A lead ore, galena, consisting mainly of lead(II) sulfide, is the principal source of lead. To obtain the lead, the ore is first heated in the air to form lead oxide. PbS ( s ) + 3 2 O 2 ( g ) → PbO ( s ) + SO 2 ( g ) Δ H = − 415.4 kJ The oxide is then reduced to metal with carbon. PbO ( s ) + C ( s ) → Pb ( s ) + CO ( g ) Δ H = + 108.5 kJ Calculate Δ H for the reaction of one mole of lead(II) sulfide with oxygen and carbon, forming lead, sulfur dioxide, and carbon monoxide.
A lead ore, galena, consisting mainly of lead(II) sulfide, is the principal source of lead. To obtain the lead, the ore is first heated in the air to form lead oxide. PbS ( s ) + 3 2 O 2 ( g ) → PbO ( s ) + SO 2 ( g ) Δ H = − 415.4 kJ The oxide is then reduced to metal with carbon. PbO ( s ) + C ( s ) → Pb ( s ) + CO ( g ) Δ H = + 108.5 kJ Calculate Δ H for the reaction of one mole of lead(II) sulfide with oxygen and carbon, forming lead, sulfur dioxide, and carbon monoxide.
Solution Summary: The author explains that Hess's law states that enthalpy is a state function as it does not depend on the path taken.
A lead ore, galena, consisting mainly of lead(II) sulfide, is the principal source of lead. To obtain the lead, the ore is first heated in the air to form lead oxide.
PbS
(
s
)
+
3
2
O
2
(
g
)
→
PbO
(
s
)
+
SO
2
(
g
)
Δ
H
=
−
415.4
kJ
The oxide is then reduced to metal with carbon.
PbO
(
s
)
+
C
(
s
)
→
Pb
(
s
)
+
CO
(
g
)
Δ
H
=
+
108.5
kJ
Calculate ΔH for the reaction of one mole of lead(II) sulfide with oxygen and carbon, forming lead, sulfur dioxide, and carbon monoxide.
Determine the bond energy for HCI (
in kJ/mol HCI) using he balanced
cremiculequecticnand bund energles
listed? also c double bond to N is
615, read numbets carefully please!!!!
Determine the bund energy for
UCI (in kJ/mol cl) using me
balanced chemical equation and
bund energies listed?
51
(My (9) +312(g)-73(g) + 3(g)
=-330. KJ
спод
bond energy
Hryn
H-H
bond
band
432
C-1 413
C=C 839 NH
391
C=O 1010
S-1 343
6-H
02 498
N-N
160
467
N=N
C-C
341
CL-
243
418
339 N-Br
243
C-O
358
Br-Br
C=C
C-Br 274
193
614
(-1 216 (=olin (02) 799
C=N
618
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