Select a random sample of 15 individuals and test one or more of the hypotheses in Exercise 1 by using the t test. Use α = 0.05. The Data Bank is found in Appendix B, or on the World Wide Web by following links from www.mhhe.com/math/stats/bluman/ 1. From the Data Bank, select a random sample of at least 30 individuals, and test one or more of the following hypotheses by using the z test. Use α = 0.05. a . For serum cholesterol, H 0 : μ = 220 milligram percent (mg%). Use σ = 5. b . For systolic pressure, H 0 : μ = 120 millimeters of mercury (mm Hg). Use σ = 13. c . For IQ, H 0 : μ = 100. Use σ = 15. d . For sodium level, H 0 : μ = 140 milliequivalents per liter (mEq/l). Use σ = 6.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 8, Problem 2DA

Select a random sample of 15 individuals and test one or more of the hypotheses in Exercise 1 by using the t test. Use α = 0.05.

The Data Bank is found in Appendix B, or on the World Wide Web by following links from www.mhhe.com/math/stats/bluman/

1. From the Data Bank, select a random sample of at least 30 individuals, and test one or more of the following hypotheses by using the z test. Use α = 0.05.

a. For serum cholesterol, H₀: μ = 220 milligram percent (mg%). Use σ = 5.

b. For systolic pressure, H₀: μ = 120 millimeters of mercury (mm Hg). Use σ = 13.

c. For IQ, H₀: μ = 100. Use σ = 15.

d. For sodium level, H₀: μ = 140 milliequivalents per liter (mEq/l). Use σ = 6.

a.

Expert Solution

To determine

To test: The claim that $H0:μ=220$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

Explanation of Solution

Answer will vary. One of the possible answers is given below:

Given info:

Claim: $H0:μ=220$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=220$

Alternative hypothesis:

$H1:μ≠220$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Serum cholesterol.
In Perform hypothesis test, enter the test mean as 220.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 1

From the output, the test value is –1.03 and the P-value is 0.322.

Make the Decision:

Decision rule:

If $P-value≤α$ , reject the null hypothesis

If $P-value>α$ , do not reject the null hypothesis.

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.322)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

b.

Expert Solution

To determine

To test: The claim that $H0:μ=120$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average systolic pressure is differs from 120 millimeters of mercury (mm Hg).

Explanation of Solution

Given info:

Claim: $H0:μ=120$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=120$

Alternative hypothesis:

$H1:μ≠120$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Systolic pressure.
In Perform hypothesis test, enter the test mean as 120.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 2

From the output, the test value is 4.19 and the P-value is 0.001.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average systolic pressure is differs from 120 millimetres of mercury (mm Hg).

c.

Expert Solution

To determine

To test: The claim that $H0:μ=100$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average IQ score is differs from 100.

Explanation of Solution

Given info:

Claim: $H0:μ=100$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=100$

Alternative hypothesis:

$H1:μ≠100$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of IQ.
In Perform hypothesis test, enter the test mean as 100.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 3

From the output, the test value is 4.29 and the P-value is 0.000.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average IQ score is differs from 100.

d.

Expert Solution

To determine

To test: The claim that $H0:μ=140$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average sodium level is 140.

Explanation of Solution

Given info:

Claim: $H0:μ=140$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=140$

Alternative hypothesis:

$H1:μ≠140$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Sodium level.
In Perform hypothesis test, enter the test mean as 140.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 4

From the output, the test value is 0.77 and the P-value is 0.456.

Make the Decision:

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.456)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average sodium level is 140.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Calculate the 90% confidence interval for the population mean difference using the data in the attached image. I need to see where I went wrong.

Microsoft Excel snapshot for random sampling: Also note the formula used for the last column 02 x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51)) A B 1 No. States 2 1 ALABAMA Rand No. 0.925957526 3 2 ALASKA 0.372999976 4 3 ARIZONA 0.941323044 5 4 ARKANSAS 0.071266381 Random Sample CALIFORNIA NORTH CAROLINA ARKANSAS WASHINGTON G7 Microsoft Excel snapshot for systematic sampling: xfx INDEX(SD52:50551, F7) A B E F G 1 No. States Rand No. Random Sample population 50 2 1 ALABAMA 0.5296685 NEW HAMPSHIRE sample 10 3 2 ALASKA 0.4493186 OKLAHOMA k 5 4 3 ARIZONA 0.707914 KANSAS 5 4 ARKANSAS 0.4831379 NORTH DAKOTA 6 5 CALIFORNIA 0.7277162 INDIANA Random Sample Sample Name 7 6 COLORADO 0.5865002 MISSISSIPPI 8 7:ONNECTICU 0.7640596 ILLINOIS 9 8 DELAWARE 0.5783029 MISSOURI 525 10 15 INDIANA MARYLAND COLORADO

Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined. 1.What percent of the refunds are more than $3,500? 2. What percent of the refunds are more than $3500 but less than $3579? 3. What percent of the refunds are more than $3325 but less than $3579?

Answer 2

Textbook Question

Chapter 8, Problem 2DA

Select a random sample of 15 individuals and test one or more of the hypotheses in Exercise 1 by using the t test. Use α = 0.05.

The Data Bank is found in Appendix B, or on the World Wide Web by following links from www.mhhe.com/math/stats/bluman/

1. From the Data Bank, select a random sample of at least 30 individuals, and test one or more of the following hypotheses by using the z test. Use α = 0.05.

a. For serum cholesterol, H₀: μ = 220 milligram percent (mg%). Use σ = 5.

b. For systolic pressure, H₀: μ = 120 millimeters of mercury (mm Hg). Use σ = 13.

c. For IQ, H₀: μ = 100. Use σ = 15.

d. For sodium level, H₀: μ = 140 milliequivalents per liter (mEq/l). Use σ = 6.

a.

Expert Solution

To determine

To test: The claim that $H0:μ=220$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

Explanation of Solution

Answer will vary. One of the possible answers is given below:

Given info:

Claim: $H0:μ=220$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=220$

Alternative hypothesis:

$H1:μ≠220$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Serum cholesterol.
In Perform hypothesis test, enter the test mean as 220.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 1

From the output, the test value is –1.03 and the P-value is 0.322.

Make the Decision:

Decision rule:

If $P-value≤α$ , reject the null hypothesis

If $P-value>α$ , do not reject the null hypothesis.

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.322)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

b.

Expert Solution

To determine

To test: The claim that $H0:μ=120$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average systolic pressure is differs from 120 millimeters of mercury (mm Hg).

Explanation of Solution

Given info:

Claim: $H0:μ=120$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=120$

Alternative hypothesis:

$H1:μ≠120$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Systolic pressure.
In Perform hypothesis test, enter the test mean as 120.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 2

From the output, the test value is 4.19 and the P-value is 0.001.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average systolic pressure is differs from 120 millimetres of mercury (mm Hg).

c.

Expert Solution

To determine

To test: The claim that $H0:μ=100$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average IQ score is differs from 100.

Explanation of Solution

Given info:

Claim: $H0:μ=100$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=100$

Alternative hypothesis:

$H1:μ≠100$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of IQ.
In Perform hypothesis test, enter the test mean as 100.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 3

From the output, the test value is 4.29 and the P-value is 0.000.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average IQ score is differs from 100.

d.

Expert Solution

To determine

To test: The claim that $H0:μ=140$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average sodium level is 140.

Explanation of Solution

Given info:

Claim: $H0:μ=140$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=140$

Alternative hypothesis:

$H1:μ≠140$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Sodium level.
In Perform hypothesis test, enter the test mean as 140.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 4

From the output, the test value is 0.77 and the P-value is 0.456.

Make the Decision:

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.456)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average sodium level is 140.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 8, Problem 2DA

Select a random sample of 15 individuals and test one or more of the hypotheses in Exercise 1 by using the t test. Use α = 0.05.

The Data Bank is found in Appendix B, or on the World Wide Web by following links from www.mhhe.com/math/stats/bluman/

1. From the Data Bank, select a random sample of at least 30 individuals, and test one or more of the following hypotheses by using the z test. Use α = 0.05.

a. For serum cholesterol, H₀: μ = 220 milligram percent (mg%). Use σ = 5.

b. For systolic pressure, H₀: μ = 120 millimeters of mercury (mm Hg). Use σ = 13.

c. For IQ, H₀: μ = 100. Use σ = 15.

d. For sodium level, H₀: μ = 140 milliequivalents per liter (mEq/l). Use σ = 6.

a.

Expert Solution

To determine

To test: The claim that $H0:μ=220$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

Explanation of Solution

Answer will vary. One of the possible answers is given below:

Given info:

Claim: $H0:μ=220$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=220$

Alternative hypothesis:

$H1:μ≠220$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Serum cholesterol.
In Perform hypothesis test, enter the test mean as 220.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 1

From the output, the test value is –1.03 and the P-value is 0.322.

Make the Decision:

Decision rule:

If $P-value≤α$ , reject the null hypothesis

If $P-value>α$ , do not reject the null hypothesis.

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.322)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

b.

Expert Solution

To determine

To test: The claim that $H0:μ=120$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average systolic pressure is differs from 120 millimeters of mercury (mm Hg).

Explanation of Solution

Given info:

Claim: $H0:μ=120$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=120$

Alternative hypothesis:

$H1:μ≠120$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Systolic pressure.
In Perform hypothesis test, enter the test mean as 120.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 2

From the output, the test value is 4.19 and the P-value is 0.001.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average systolic pressure is differs from 120 millimetres of mercury (mm Hg).

c.

Expert Solution

To determine

To test: The claim that $H0:μ=100$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average IQ score is differs from 100.

Explanation of Solution

Given info:

Claim: $H0:μ=100$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=100$

Alternative hypothesis:

$H1:μ≠100$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of IQ.
In Perform hypothesis test, enter the test mean as 100.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 3

From the output, the test value is 4.29 and the P-value is 0.000.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average IQ score is differs from 100.

d.

Expert Solution

To determine

To test: The claim that $H0:μ=140$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average sodium level is 140.

Explanation of Solution

Given info:

Claim: $H0:μ=140$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=140$

Alternative hypothesis:

$H1:μ≠140$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Sodium level.
In Perform hypothesis test, enter the test mean as 140.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 4

From the output, the test value is 0.77 and the P-value is 0.456.

Make the Decision:

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.456)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average sodium level is 140.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 8, Problem 2DA

Select a random sample of 15 individuals and test one or more of the hypotheses in Exercise 1 by using the t test. Use α = 0.05.

The Data Bank is found in Appendix B, or on the World Wide Web by following links from www.mhhe.com/math/stats/bluman/

1. From the Data Bank, select a random sample of at least 30 individuals, and test one or more of the following hypotheses by using the z test. Use α = 0.05.

a. For serum cholesterol, H₀: μ = 220 milligram percent (mg%). Use σ = 5.

b. For systolic pressure, H₀: μ = 120 millimeters of mercury (mm Hg). Use σ = 13.

c. For IQ, H₀: μ = 100. Use σ = 15.

d. For sodium level, H₀: μ = 140 milliequivalents per liter (mEq/l). Use σ = 6.

a.

Expert Solution

To determine

To test: The claim that $H0:μ=220$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

Explanation of Solution

Answer will vary. One of the possible answers is given below:

Given info:

Claim: $H0:μ=220$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=220$

Alternative hypothesis:

$H1:μ≠220$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Serum cholesterol.
In Perform hypothesis test, enter the test mean as 220.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 1

From the output, the test value is –1.03 and the P-value is 0.322.

Make the Decision:

Decision rule:

If $P-value≤α$ , reject the null hypothesis

If $P-value>α$ , do not reject the null hypothesis.

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.322)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

b.

Expert Solution

To determine

To test: The claim that $H0:μ=120$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average systolic pressure is differs from 120 millimeters of mercury (mm Hg).

Explanation of Solution

Given info:

Claim: $H0:μ=120$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=120$

Alternative hypothesis:

$H1:μ≠120$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Systolic pressure.
In Perform hypothesis test, enter the test mean as 120.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 2

From the output, the test value is 4.19 and the P-value is 0.001.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average systolic pressure is differs from 120 millimetres of mercury (mm Hg).

c.

Expert Solution

To determine

To test: The claim that $H0:μ=100$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average IQ score is differs from 100.

Explanation of Solution

Given info:

Claim: $H0:μ=100$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=100$

Alternative hypothesis:

$H1:μ≠100$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of IQ.
In Perform hypothesis test, enter the test mean as 100.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 3

From the output, the test value is 4.29 and the P-value is 0.000.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average IQ score is differs from 100.

d.

Expert Solution

To determine

To test: The claim that $H0:μ=140$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average sodium level is 140.

Explanation of Solution

Given info:

Claim: $H0:μ=140$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=140$

Alternative hypothesis:

$H1:μ≠140$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Sodium level.
In Perform hypothesis test, enter the test mean as 140.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 4

From the output, the test value is 0.77 and the P-value is 0.456.

Make the Decision:

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.456)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average sodium level is 140.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

a.

Expert Solution

To determine

To test: The claim that $H0:μ=220$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

Explanation of Solution

Answer will vary. One of the possible answers is given below:

Given info:

Claim: $H0:μ=220$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=220$

Alternative hypothesis:

$H1:μ≠220$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Serum cholesterol.
In Perform hypothesis test, enter the test mean as 220.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 1

From the output, the test value is –1.03 and the P-value is 0.322.

Make the Decision:

Decision rule:

If $P-value≤α$ , reject the null hypothesis

If $P-value>α$ , do not reject the null hypothesis.

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.322)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

b.

Expert Solution

To determine

To test: The claim that $H0:μ=120$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average systolic pressure is differs from 120 millimeters of mercury (mm Hg).

Explanation of Solution

Given info:

Claim: $H0:μ=120$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=120$

Alternative hypothesis:

$H1:μ≠120$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Systolic pressure.
In Perform hypothesis test, enter the test mean as 120.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 2

From the output, the test value is 4.19 and the P-value is 0.001.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average systolic pressure is differs from 120 millimetres of mercury (mm Hg).

c.

Expert Solution

To determine

To test: The claim that $H0:μ=100$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average IQ score is differs from 100.

Explanation of Solution

Given info:

Claim: $H0:μ=100$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=100$

Alternative hypothesis:

$H1:μ≠100$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of IQ.
In Perform hypothesis test, enter the test mean as 100.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 3

From the output, the test value is 4.29 and the P-value is 0.000.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average IQ score is differs from 100.

d.

Expert Solution

To determine

To test: The claim that $H0:μ=140$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average sodium level is 140.

Explanation of Solution

Given info:

Claim: $H0:μ=140$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=140$

Alternative hypothesis:

$H1:μ≠140$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Sodium level.
In Perform hypothesis test, enter the test mean as 140.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 4

From the output, the test value is 0.77 and the P-value is 0.456.

Make the Decision:

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.456)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average sodium level is 140.

Answer 8

a.

Expert Solution

To determine

To test: The claim that $H0:μ=220$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

Explanation of Solution

Answer will vary. One of the possible answers is given below:

Given info:

Claim: $H0:μ=220$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=220$

Alternative hypothesis:

$H1:μ≠220$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Serum cholesterol.
In Perform hypothesis test, enter the test mean as 220.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 1

From the output, the test value is –1.03 and the P-value is 0.322.

Make the Decision:

Decision rule:

If $P-value≤α$ , reject the null hypothesis

If $P-value>α$ , do not reject the null hypothesis.

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.322)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

To test: The claim that $H0:μ=220$ .

Answer 13

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

Answer 14

Explanation of Solution

Answer will vary. One of the possible answers is given below:

Given info:

Claim: $H0:μ=220$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=220$

Alternative hypothesis:

$H1:μ≠220$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Serum cholesterol.
In Perform hypothesis test, enter the test mean as 220.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 1

From the output, the test value is –1.03 and the P-value is 0.322.

Make the Decision:

Decision rule:

If $P-value≤α$ , reject the null hypothesis

If $P-value>α$ , do not reject the null hypothesis.

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.322)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average serum cholesterol level is 220 milligram percent (mg%).

Answer 15

b.

Expert Solution

To determine

To test: The claim that $H0:μ=120$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average systolic pressure is differs from 120 millimeters of mercury (mm Hg).

Explanation of Solution

Given info:

Claim: $H0:μ=120$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=120$

Alternative hypothesis:

$H1:μ≠120$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Systolic pressure.
In Perform hypothesis test, enter the test mean as 120.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 2

From the output, the test value is 4.19 and the P-value is 0.001.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average systolic pressure is differs from 120 millimetres of mercury (mm Hg).

Answer 16

b.

Expert Solution

Answer 17

b.

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

To test: The claim that $H0:μ=120$ .

Answer 20

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average systolic pressure is differs from 120 millimeters of mercury (mm Hg).

Answer 21

Explanation of Solution

Given info:

Claim: $H0:μ=120$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=120$

Alternative hypothesis:

$H1:μ≠120$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Systolic pressure.
In Perform hypothesis test, enter the test mean as 120.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 2

From the output, the test value is 4.19 and the P-value is 0.001.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average systolic pressure is differs from 120 millimetres of mercury (mm Hg).

Answer 22

c.

Expert Solution

To determine

To test: The claim that $H0:μ=100$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average IQ score is differs from 100.

Explanation of Solution

Given info:

Claim: $H0:μ=100$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=100$

Alternative hypothesis:

$H1:μ≠100$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of IQ.
In Perform hypothesis test, enter the test mean as 100.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 3

From the output, the test value is 4.29 and the P-value is 0.000.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average IQ score is differs from 100.

Answer 23

c.

Expert Solution

Answer 24

c.

Expert Solution

Answer 25

Expert Solution

Answer 26

To determine

To test: The claim that $H0:μ=100$ .

Answer 27

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average IQ score is differs from 100.

Answer 28

Explanation of Solution

Given info:

Claim: $H0:μ=100$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=100$

Alternative hypothesis:

$H1:μ≠100$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of IQ.
In Perform hypothesis test, enter the test mean as 100.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 3

From the output, the test value is 4.29 and the P-value is 0.000.

Make the Decision:

Here, the P-value is lesser than the level of significance.

That is, $P-value(=0.001)<α(=0.05)$ .

By the decision rule, the null hypothesis is rejected.

Thus, the decision is “reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average IQ score is differs from 100.

Answer 29

d.

Expert Solution

To determine

To test: The claim that $H0:μ=140$ .

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average sodium level is 140.

Explanation of Solution

Given info:

Claim: $H0:μ=140$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=140$

Alternative hypothesis:

$H1:μ≠140$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Sodium level.
In Perform hypothesis test, enter the test mean as 140.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 4

From the output, the test value is 0.77 and the P-value is 0.456.

Make the Decision:

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.456)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average sodium level is 140.

Answer 30

d.

Expert Solution

Answer 31

d.

Expert Solution

Answer 32

Expert Solution

Answer 33

To determine

To test: The claim that $H0:μ=140$ .

Answer 34

Answer to Problem 2DA

The conclusion is that there is sufficient evidence to infer that the average sodium level is 140.

Answer 35

Explanation of Solution

Given info:

Claim: $H0:μ=140$ , $n=15$ and $α=0.05$ .

Calculation:

State the null and alternative hypotheses:

Null hypothesis:

$H0:μ=140$

Alternative hypothesis:

$H1:μ≠140$

Test statistic value and P-value:

Software procedure:

Step by step procedure to obtain the test value using the MINITAB software:

Choose Stat > Basic Statistics > 1-Sample t.
In Samples in Column, enter the column of Sodium level.
In Perform hypothesis test, enter the test mean as 140.
Check Options; enter Confidence level as 95%.
Choose not equal in alternative.
Click OK in all dialogue boxes.

Output using the MINITAB software is given below:

ALEK 360 ELEM STAT, Chapter 8, Problem 2DA , additional homework tip 4

From the output, the test value is 0.77 and the P-value is 0.456.

Make the Decision:

Here, the P-value is greater than the level of significance.

That is, $P-value(=0.456)>α(=0.05)$ .

By the decision rule, the null hypothesis is not rejected.

Thus, the decision is “fail to reject the null hypothesis”.

Summarize the result:

There is sufficient evidence to infer that the average sodium level is 140.

Answer 36

Ch. 8.1 - Applying the Concepts 81 Eggs and Your Health The...Ch. 8.1 - Define null and alternative hypotheses, and give...Ch. 8.1 - What is meant by a type I error? A type II error?...Ch. 8.1 - What is meant by a statistical test?Ch. 8.1 - Explain the difference between a one-tailed and a...Ch. 8.1 - What is meant by the critical region? The...Ch. 8.1 - What symbols are used to represent the null...Ch. 8.1 - What symbols are used to represent the...Ch. 8.1 - Explain what is meant by a significant difference.Ch. 8.1 - When should a one-tailed test be used? A...

Videos

Answer to Problem 2DA

Explanation of Solution

Answer to Problem 2DA

Explanation of Solution

Answer to Problem 2DA

Explanation of Solution

Answer to Problem 2DA

Explanation of Solution

Want to see more full solutions like this?

Chapter 8 Solutions