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As shown, a light string that does not stretch changes from horizontal to vertical as it passes over the edge of a table. The string connects m1, a 3.50-kg block originally at rest on the horizontal table at a height h = 1.20 m above the floor, to m2, a hanging 1.90-kg block originally a distance d = 0.900 m above the floor. Neither the surface of the table nor its edge exerts a
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- A stacked pair of books with masses m1= 2.0 kg (bottom book) and m2 = 1.5 kg (top book) are tossed onto a table. The books strike the table with no vertical velocity and their common horizontal speed is ?o = 0.75 m/s. The kinetic friction coefficient between the bottom book and the table is ?k1=0.45; the kinetic and static friction coefficients between the two books are ?k2=0.3 and ?s2= 0.4. Find the final horizontal position of each book relative to the spot where the stack hits the table.arrow_forwardProblem 6. A 6.0kg block is placed on top of a 9.0kg block. A horizontal force of 50.0N is applied at an angle to the 9.0kg block, and the 6.0kg block is tied to the wall by a rope. The coefficient of kinetic friction between the two blocks is 0.25, and the coefficient of friction between the 9.0kg block and the ground surface is 0.30. (a) Draw a free body diagram for each block and identify the action-reaction forces between the blocks. (b) Determine the tension in the rope. (c) Determine the magnitude of the acceleration of each block. 6.0kg F = 50.0N 15° 9.0kgarrow_forwardThe distance between two telephone poles is d = 54.0 m. When a 1.20 kg bird lands on the telephone wire midway between the poles, the wire sags h = 0.206 m. (a) Draw a free-body diagram of the midpoint of the wire (where the bird is perched). mg O X* (b) How much tension (in N) does the bird produce in the wire? Ignore the weight of the wire. 3.15 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N Need Help? Read Itarrow_forward
- A child is playing on a hill with a cardboard box. The combined mass of child and box is ? = 120 kg. He climbs into box, which is initially at rest, at the top of the hill. The hill is inclined at an angle of 30 degrees with respect to the horizontal. The coefficients of static and kinetic friction between the box and the hill are mu s = 0.4 and mu k = 0.2. Consider that the box (with child inside) has begun to slide down the hill (you can assume that it has been given a brief push to get it started moving). What is the magnitude of the acceleration of the box? b. If the hill is 4 m tall, what is the child’s speed when he reaches the bottom? c. At the bottom of the hill, the ground becomes level (horizontal), but the coefficients of friction do not change. How far does the child slide before he comes to a stop? Thank you in advance, it's a lengthy question and I really need help :)arrow_forwardThe block shown in the figure is sliding along a frictionless horizontal surface The block's mass is m = 4.80 kg,the magnitude of the applied force is F = 26.5 N, and the angle of the applied force F from the horizontal is θ = 28.0°. Determine the magnitude n of the normal force acting on the block.arrow_forwardTwo roofers are installing a new roof. Bob is sitting on the top of the roof that is angled at 23.5 degrees from the horizontal. Nate is sitting 4.1 m further down the roof. In order to get a box of shingles to Nate, Bob just slides the box directly down to him. If the coefficient of kinetic friction for the box and roof is 0.5, then with what speed should Bob initially push the box so that it slides to a stop right as it reaches the Nate?arrow_forward
- please type your solutions and or diagram them so that they are easy to read i have bad eyesight and if needed please also show all calculations these would need to be typed as well thank youarrow_forwardMany birds can attain very high speeds when diving. Using radar, scientists measured the altitude of a barn swallow in a vertical dive; it dropped 208 m in 3.0 s. The mass of the swallow was estimated to be 0.018 kg, and its cross-section area as 5.6 x 10-4 m2. What was the drag coefficient for this swallow as it dove?arrow_forwardA 1500-N crate is to be held in place on a ramp that rises at 30.0° above the horizontal (see figure). The massless rope attached to the crate makes a 22.0° angle above the surface of the ramp. The coefficients of friction between the crate and the surface of the ramp are uk = 0.450 and us = 0.650. The pulley has no appreciable mass or friction. What is the MAXIMUM weight w that can be used to hold this crate stationary on the ramp? %3D W= ? Crate 22.0° Ramp 30.00arrow_forward
- You are a bully. You pin a 48 kg dweeb to a wall so that his feet aren't touching the ground. Your arm is extended so that it makes an angle 28 degrees with the horizontal. The dweeb's back is so sweaty with fear that there is no friction between his back and the wall. What is the magnitude of the force , in N, you must apply to keep the dweeb in equilibrium? (Use g = 10 m/s2) This scenario is represented schematically below. Unfortunately for you, years later the dweeb is your boss and he makes your life miserable. (Please answer to the fourth decimal place - i.e 12.3445)arrow_forwardA stone has a mass of 8.79 g and is wedged into the tread of an automobile tire, as the drawing shows. The coefficient of static friction between the stone and each side of the tread channel is 0.818. When the tire surface is rotating at 10.9m/s, the stone flies out the tread. The magnitude FN of the normal force that each side of the tread channel exerts on the stone is 2.46 N. Assume that only static friction supplies the centripetal force, and determines the radius r of the tire (in terms of m)arrow_forwardTwo crates of fruit are released from the top of a ramp inclined at 30 degrees from the horizontal and 4.5 meter long. The two crates consist of an apple crate of mass 20 kg that is placed in front of a watermelon crate of mass 80 kg. The apple crate has a coefficient of friction of 0.20 while the watermelon crate has a coefficient of friction of 0.15. How long does it take the apple crate to reach the bottom of the incline if it needs to travel a distance of 4.5 meters?arrow_forward
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