(a)
To write and solve two system of equations in order to find the value of and
(a)
Answer to Problem 20PS
The decoding matrix is-
Explanation of Solution
Given Information:
The following cryptogram is given:
Consider the following cryptogram
So, the coded message is-
The decoding matrix is:
It is also given that
Now, it is given that-
So, the system of linear equations are as follows-
And
Now, the augmented matrix for both the equations are:
Applying the Gauss Jordan elimination and applying row transformations:
So, the values are −
So, the decoding matrix is −
b.
To decode the message.
b.
Answer to Problem 20PS
The message is -
JOHN RETURN TO BASE
Explanation of Solution
Now, the message can be decoded by multiplying the decoding matrix with the coded matrix as follows-
Therefore, the un-coded matrices are:
So, the message in cryptography can be written as
Hence, the original message is JOHN RETURN TO BASE.
Chapter 8 Solutions
EBK PRECALCULUS W/LIMITS
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning