Statistics: The Art and Science of Learning from Data (4th Edition)
4th Edition
ISBN: 9780321997838
Author: Alan Agresti, Christine A. Franklin, Bernhard Klingenberg
Publisher: PEARSON
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Chapter 8, Problem 111CP
a.
To determine
Explain the effect on n of increasing the confidence level.
b.
To determine
Explain the effect on n of decreasing the margin of error.
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Chapter 8 Solutions
Statistics: The Art and Science of Learning from Data (4th Edition)
Ch. 8.1 - Health care A study dealing with health care...Ch. 8.1 - Video on demand A recent study from Nielsen...Ch. 8.1 - Projecting winning candidate News coverage during...Ch. 8.1 - Believe in hell? Using the General Social Survey...Ch. 8.1 - Government spying In 2014, news reports worldwide...Ch. 8.1 - Game apps The Google Play app store for...Ch. 8.1 - Nutrient effect on growth rate Researchers are...Ch. 8.1 - Believe in heaven? When a GSS asked 1326 subjects,...Ch. 8.1 - Feel lonely often? The GSS has asked On how many...Ch. 8.1 - CI for loneliness Refer to the previous exercise....
Ch. 8.2 - Putin A Gallup poll of 2000 Russians taken between...Ch. 8.2 - Flu shot In a clinical study (the same as...Ch. 8.2 - How green are you? When the 2000 GSS asked...Ch. 8.2 - Make industry help environment? When the 2006 GSS...Ch. 8.2 - Favor death penalty In the 2012 General Social...Ch. 8.2 - Oppose death penalty Refer to the previous...Ch. 8.2 - Stem cell research A Harris poll of a random...Ch. 8.2 - z-score and confidence level Which z-score is used...Ch. 8.2 - Believe in ghosts A Harris poll of a random sample...Ch. 8.2 - Stem cell research and religion In Exercise 8.18,...Ch. 8.2 - Fear of breast cancer A recent survey of 1000...Ch. 8.2 - Chicken breast In a 2014 Consumer Reports article...Ch. 8.2 - Same-sex marriage A national survey by the Pew...Ch. 8.2 - Exit poll predictions A national television...Ch. 8.2 - Exit poll with smaller sample In the previous...Ch. 8.2 - Simulating confidence intervals Repeat the...Ch. 8.2 - Simulating confidence intervals with poor coverage...Ch. 8.3 - Females ideal number of children The 2012 General...Ch. 8.3 - Males ideal number of children Refer to the...Ch. 8.3 - Using t-table Using Table B, the web app, software...Ch. 8.3 - Anorexia in teenage girls A study6 compared...Ch. 8.3 - Talk time on smartphones One feature smartphone...Ch. 8.3 - Heights of seedlings Exercise 8.7 reported heights...Ch. 8.3 - Buy it now Example 6 mentioned closing prices for...Ch. 8.3 - Time spent on e-mail When the GSS asked n = 1050...Ch. 8.3 - Grandmas using e-mail For the question about...Ch. 8.3 - Prob. 38PBCh. 8.3 - Prob. 39PBCh. 8.3 - Political views The General Social Survey asks...Ch. 8.3 - Prob. 41PBCh. 8.3 - Prob. 42PBCh. 8.3 - Effect of confidence level Find the margin of...Ch. 8.3 - Prob. 44PBCh. 8.3 - Number of children For the question, How many...Ch. 8.3 - Prob. 46PBCh. 8.4 - South Africa study The researcher planning the...Ch. 8.4 - Binge drinkers A study at the Harvard School of...Ch. 8.4 - Prob. 49PBCh. 8.4 - Prob. 50PBCh. 8.4 - Prob. 51PBCh. 8.4 - Farm size An estimate is needed of the mean...Ch. 8.4 - Prob. 53PBCh. 8.4 - Prob. 54PBCh. 8.4 - Prob. 55PBCh. 8.4 - Prob. 56PBCh. 8.4 - Prob. 57PBCh. 8.4 - Prob. 58PBCh. 8.5 - Why bootstrap? Explain the purpose of using the...Ch. 8.5 - Estimating variability Refer to Example 11 about...Ch. 8.5 - Bootstrap interval for the mean In 2014, the...Ch. 8.5 - Prob. 62PBCh. 8 - Unemployed college grads The U.S Bureau of the...Ch. 8 - Prob. 64CPCh. 8 - Prob. 65CPCh. 8 - Born again A poll of a random sample of n = 2000...Ch. 8 - Life after death The variable POSTLIFE in the 2012...Ch. 8 - Prob. 68CPCh. 8 - Prob. 69CPCh. 8 - Prob. 70CPCh. 8 - Prob. 71CPCh. 8 - Wife supporting husband Consider the statement...Ch. 8 - Legalize marijuana? The General Social Survey has...Ch. 8 - Prob. 74CPCh. 8 - Streaming A Harris Poll of 2300 U.S. adults...Ch. 8 - Prob. 76CPCh. 8 - Prob. 77CPCh. 8 - Grandpas using e-mail When the GSS asked in 2012,...Ch. 8 - Prob. 79CPCh. 8 - Prob. 80CPCh. 8 - Fuel efficiency The government website...Ch. 8 - Prob. 82CPCh. 8 - Prob. 83CPCh. 8 - Prob. 84CPCh. 8 - Prob. 85CPCh. 8 - Prob. 86CPCh. 8 - Prob. 87CPCh. 8 - Revisiting mountain bikes Use the Mountain Bike...Ch. 8 - Prob. 89CPCh. 8 - Prob. 90CPCh. 8 - Prob. 91CPCh. 8 - Prob. 92CPCh. 8 - Working mother In response to the statement on a...Ch. 8 - Miami spring break For a trip to Miami, Florida,...Ch. 8 - Prob. 95CPCh. 8 - Prob. 96CPCh. 8 - Prob. 97CPCh. 8 - Prob. 98CPCh. 8 - Prob. 99CPCh. 8 - Prob. 100CPCh. 8 - Kicking accuracy A football coach decides to...Ch. 8 - Prob. 103CPCh. 8 - Prob. 104CPCh. 8 - Prob. 106CPCh. 8 - Width of a confidence interval Why are confidence...Ch. 8 - Prob. 108CPCh. 8 - Prob. 109CPCh. 8 - Prob. 110CPCh. 8 - Prob. 111CPCh. 8 - Prob. 112CPCh. 8 - Prob. 113CPCh. 8 - Prob. 114CPCh. 8 - Prob. 115CPCh. 8 - Prob. 116CPCh. 8 - Prob. 117CPCh. 8 - Prob. 118CPCh. 8 - Prob. 119CPCh. 8 - Prob. 120CPCh. 8 - Prob. 121CPCh. 8 - Prob. 122CPCh. 8 - Prob. 123CPCh. 8 - Why called degrees of freedom? You know the sample...Ch. 8 - Prob. 125CPCh. 8 - Prob. 126CPCh. 8 - Median as point estimate When the population...
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- You want to obtain a sample to estimate a population proportion . Based on previous evidence, you believe the population proportion is approximately p = 0.81 . You would like to be 98% confident that your esimate is within 5\% of the true population proportion. How large of a sample size is required?arrow_forwardWhat size sample should be obtained to be 95% confident that the sample proportion will not differ from the true proportion by more than 2%?arrow_forwardCan the population support of samples completed ? (margin of error =5%) (Z=1.96,p=0.6)arrow_forward
- You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately p^=67%. You would like to be 90% confident that your esimate is within 5% of the true population proportion. How large of a sample size is required?Do not round mid-calculation.arrow_forwardUse paired t-interval procedure to determine a 90% confidence interval for the difference between the mean of x and mean of y. (X, Y) = (49.3, 49), (43.2, 42), (50.4, 50), (36.3, 37), (52.3, 50)arrow_forwardA random variable of 7 independent observation of a normal variable gave Ex = 35.9 Ex2 = 186.19 E(x-x)2 = 2.074 Calculate The sample mean The sample variance A 90% confidence interval for the population meanarrow_forward
- A student conducted a test at 0.05, and she found the 95% CI to be [4.79,7.25]. The mean for the sample is 6.12. Is the conclusion for the test that there is a significant difference or that there is not a significant difference? You should fully explain how you can use this information to draw a conclusion.arrow_forwardCan you help me with C thank you! It's finding the sample size.arrow_forwardYou want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately ˆpp^ = 60%`. You would like to be 95% confident that your esimate is within 2% of the true population proportion. How large of a sample size is required?arrow_forward
- In general terms, describe the procedure used to perform the Sign Test when testing for equal means from two dependent populations (i.e. H0 : µD = 0 versus H1 : µD 6= 0 where µD = mean of the difference “Pre-Post). If needed, construct a sample table of data to explain the procedure.arrow_forwardThe odds difference = exp((0.15*20)-(0.15*30)), the standard error(se) = 0.06 which is on the scale of the linear predictor and not the odds. How to find the CI of the odds difference? Using simply the odds difference +- 1.96*se is incorrect. Pls explain alsoarrow_forwardDr. Nunez wants to estimate the average lung capacity of adults in her state. She plans on taking a sample of n adults to construct a 99% confidence interval for the mean lung capacity She wants the margin of error to be no more than 100mL She's willing to use sigma = 300mL as an estimate for the population standard deviationarrow_forward
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