Physics Laboratory Manual
4th Edition
ISBN: 9781133950639
Author: David Loyd
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 7A, Problem 4PLA
Suppose a block of mass 25.0 kg rests on a horizontal plane, and the coefficient of static friction between the surfaces is 0.220. (a) What is the maximum possible static frictional force that could act on the block? ______N (b) What is the actual static frictional force that acts on the block if an external force of 25.0 N acts horizontally on the block? ______N Assume g = 9.80 m/s2. Show your work and explain both answers.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Suppose a 25.0 kg block rests on a horizontal plane, and the static friction coefficient between the surfaces is 0.220. (a) What is the maximum allowable static frictional force that could act on the block? (b) What is the actual static frictional force acting on the block if a 25.0 N external force acts horizontally? Assume g = 9.80 m/s2.
Suppose a block of mass 25.0kg rests on a horizontal plane, and the coefficient of static friction between the surfaces is 0.220. (a) What is the maximum possible static frictional force that could act on the block?_____N (b)What is the actual static frictional force that acts on the block if an external force of 25.0N acts horizontally on the block?_____N
Download
DRA.jpeg
T--T
KTNCA
A force is applied to a 24 kg object and presses it against a wall. This force is just great enough to hold the
object in place (to prevent it from sliding down the wall). If the coefficient of static friction between the
object and the wall is μ = 0.27, then find the applied force.
Fapplied
M
12.
759.7_N
1537_N
1272_N
A.
B.
C.
1--1
Pigshow.jpeg
Pig show.jpeg
D.
نعم نعد
E.
F.
1608_N
871.1 N
651.2 N
MacBook Pro
Sign
Chapter 7A Solutions
Physics Laboratory Manual
Ch. 7A - Prob. 1PLACh. 7A - Static friction is (a) always less than the...Ch. 7A - The two coefficients of friction discussed in this...Ch. 7A - Suppose a block of mass 25.0 kg rests on a...Ch. 7A - For the laboratory measurement of the static...Ch. 7A - Prob. 6PLACh. 7A - Prob. 7PLACh. 7A - For either type of coefficient of friction, what...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Of the following statements, indicate on the line whether they are true (T) or false (F):___ The friction between two surfaces can be changed by changing the masses of the objects.___ The coefficient of static friction can be less than the coefficient of kinematic friction.___ When the force of friction increases, the coefficient of friction decreases.___ The only way to change the friction between two objects is by changing their masses.___ The only way to change the friction between two objects is to polish their surfaces.___ The only way to change the friction between two objects is by changing their materials.___ The value of the friction force of a body is always constant when it is staticand does not vary with the applied force.___ When a ball strikes outside the center of gravity of a baseball bat, the ball will travelfurther than if it hit the center of gravity.___ The center of gravity of a body may be outside of it.___ The center of gravity of an object depends only on the…arrow_forwardThe image below shows a box with an applied force. The static coefficient of friction between the box and surface is 1.2. 19 kg 400 N 20° (a) Determine the magnitude of the applied force along the x axis. (b) Determine the normal force as the force is applied. mumarrow_forwardA 200 N block is at rest on a 30° incline. The coefficient of friction between the block and the incline is 0.20. Compute the value of angle of friction and the value of a horizontal force P that will cause motion to impend up the incline. W=200 N P 30arrow_forward
- A block weighs 100. N and rests on a horizontal surface. If Ms = 0.50 and uk = 0.20 between the block and the horizontal surface, then (a) What is the magnitude of the frictional force acting on the block? Justify your What is the magnitude of the frictional force acting on the block if a horizontal force of 35.0 N is now used to push the block? Justify your answer with a calculation. What is the magnitude of the minimum horizontally applied force that will start the block sliding? Justify your answer with a calculation. If the magnitude of the applied horizontal force on the block is 55.0 N, what is the magnitude of the frictional force acting on the block? Justify your answer with a calculation.arrow_forward2.0 kg against a vertical wall by exerting 40 N, on it. The coefficients of static and kinetic friction 3. 10 A person holds a book of mass m = a horizontal force, Fext between the book and wall are p, = 0.6 and Hk = 0.4, respectively. The book is stationary. %3D +y Calculate a numerical value for the force (a vector) that the wall exerts on the book. Put your numerical vector answer in component form.arrow_forwardThe 633-N force is applied to the 106-kg block, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the block. The force is positive if to the right, negative if to the left. P = 633 N 38° = 0.66 H = 0.43 Answer: F = i Narrow_forward
- A crate of mass 15.0 kg rests on a level surface. If the coefficient of kinetic friction between the crate and surface is 0.440, calculate the following. (a) Calculate the normal force. (Give the magnitude.) N(b) Calculate the magnitude of the kinetic friction force when a horizontal applied force of 67.0 N moves the crate. N(c) Calculate the normal force when the 67.0-N applied force is exerted at an angle of 37.5° above the horizontal. (Give the magnitude.) N(d) Calculate the magnitude of the kinetic friction force when the 67.0-N applied force is exerted at an angle of 37.5° above the horizontal. Narrow_forwardA 50.7 kg box is resting on a horizontal floor. A force of 317.1 N directed at an angle of 34.1° below the horizontal is applied to the box. The coefficient of static friction between the box and the surface is 0.5, and the coefficient of kinetic friction is 0.2. The force of friction on the box is:arrow_forwardFrom Fig. P-014, P is directed at an angle a from x-axis and the 200 N force is acting at a slope of 5 vertical to 12 horizontal. a. Find P and a if the resultant is 500 N to the right along the x-axis. b. Find P and a if the resultant is 500 N upward to the right with a slope of 3 horizontal to 4 vertical. c. Find P and a if the resultant is zero. 12 200 N Figure P-014arrow_forward
- If the coefficient of static friction between all surfaces in contact is µg = 0.3 and a determine force P that must be applied to wedge A in order to lift the block weighing 500 N. The weight of wedge A is negligible compared to the block. B Parrow_forwardA box with mass m = 3.25 kg rests on the top of a bar. The coefficient of static friction between the box and the bar is μs = 0.71 and the coefficient of kinetic friction is μk = 0.36.Write an expression for Fm the minimum force required to produce movement of the box on the top of the bar. Fm=Solve numerically for the magnitude of the force Fm in Newtons. fm=Write an expression for a, the box's acceleration, after it begins moving. (Assume the minimum force, Fm, continues to be applied.) Solve numerically for the acceleration, a in m/s2.arrow_forwardA tool box of weighing 50.0 N rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.40, and the coefficient of kinetic friction is 0.20. If no horizontal force is applied to the box and the box is at rest, how large is the friction force exerted on the box?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Newton's First Law of Motion: Mass and Inertia; Author: Professor Dave explains;https://www.youtube.com/watch?v=1XSyyjcEHo0;License: Standard YouTube License, CC-BY