In Problems 21–26, use the description of the region R to evaluate the indicated integral. 25. ∬ R e x + y d A ; R = { ( x , y ) | − x ≤ y ≤ x , 0 ≤ x ≤ 2 }
In Problems 21–26, use the description of the region R to evaluate the indicated integral. 25. ∬ R e x + y d A ; R = { ( x , y ) | − x ≤ y ≤ x , 0 ≤ x ≤ 2 }
Solution Summary: The author explains the value of the iterated integral, which is e4-52.
In Problems 21–26, use the description of the region R to evaluate the indicated integral.
25.
∬
R
e
x
+
y
d
A
;
R
=
{
(
x
,
y
)
|
−
x
≤
y
≤
x
,
0
≤
x
≤
2
}
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
1) Find the area of the region above the x axis and to the
left of the line x = 1 bounded by the x axis, the line x = 1,
and the curve y = 4-x².
What is the area (in square units) of the region bounded by the graphs of y=x2+2, and the x axis from x= -
1 and x=2?
...
ly = x² + 2
-1
2
(А) 9
13
B
3
25
1. Find the area of the region bounded by y = 4 – x², y = x + 2, x = -2,
and x = 1.
|
2. Find the area of the region bounded y = x'/4 and y = x².
Chapter 7 Solutions
Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)
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Definite Integral Calculus Examples, Integration - Basic Introduction, Practice Problems; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=rCWOdfQ3cwQ;License: Standard YouTube License, CC-BY