The problem z = − 5 x 1 + 4 x 2 − 2 x 3 in terms of equation by using slack variable and surplus variable subjected to, − 2 x 2 + 5 x 3 ≥ 8 4 x 1 − x 2 + 3 x 3 ≤ 12 and x 1 ≥ 0 , x 2 ≥ 0 , x 3 ≥ 0 .

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Answer 1

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Chapter 7.7, Problem 1E

(a)

To determine

To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to,

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0.

(b)

To determine

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0

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(b) An otherwise fair six-sided die has been tampered with in an attempt to cheat at a dice game. The effect is that the 1 and 6 faces have a different probability of occurring than the 2, 3, 4 and 5 faces. Let θ be the probability of obtaining a 1 on this biased die. Then the outcomes of rolling the biased die have the following probability mass function. Table 1 The p.m.f. of outcomes of rolls of a biased die Outcome 1 2 3 4 5 6 Probability θ 1 4 (1 − 2θ) 1 4 (1 − 2θ) 1 4 (1 − 2θ) 1 4 (1 − 2θ) θ (i) By consideration of the p.m.f. in Table 1, explain why it is necessary for θ to be such that 0 < θ < 1/2. [2] (ii) The value of θ is unknown. Data from which to estimate the value of θ were obtained by rolling the biased die 1000 times. The result of this experiment is shown in Table 2. Table 2 Outcomes of 1000 independent rolls of a biased die Outcome 1 2 3 4 5 6 Frequency 205 154 141 165 145 190 Show that the likelihood of θ based on these data is L(θ) = C θ395 (1 − 2θ) 605 ,…

Problem: The probability density function of a random variable is given by the exponential distribution Find the probability that f(x) = {0.55e-0.55 x 0 < x, O elsewhere} a. the time to observe a particle is more than 200 microseconds. b. the time to observe a particle is less than 10 microseconds.

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Answer 2

Question

Chapter 7.7, Problem 1E

(a)

To determine

To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to,

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0.

(b)

To determine

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0

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Answer 3

Question

Chapter 7.7, Problem 1E

(a)

To determine

To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to,

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0.

(b)

To determine

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 4

Question

Chapter 7.7, Problem 1E

(a)

To determine

To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to,

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0.

(b)

To determine

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0

Expert Solution & Answer

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Answer 5

Chapter 7.7, Problem 1E

(a)

To determine

To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to,

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0.

(b)

To determine

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0

Answer 6

Chapter 7.7, Problem 1E

(a)

To determine

To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to,

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0.

Answer 7

Chapter 7.7, Problem 1E

(a)

To determine

To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to,

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0.

Answer 8

(b)

To determine

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0

Answer 9

(b)

To determine

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

Ch. 7.1 - Checkpoint 1 Graph the given...Ch. 7.1 - Prob. 2CP Ch. 7.1 - Prob. 3CP Ch. 7.1 - Prob. 4CP Ch. 7.1 - Prob. 5CP Ch. 7.1 - Checkpoint 6 Graph the feasible region of the...Ch. 7.1 - Prob. 7CP Ch. 7.1 - Match the inequality with its graph, which is one...Ch. 7.1 - Match the inequality with its graph, which is one...Ch. 7.1 - Match the inequality with its graph, which is one...

The problem z = − 5 x 1 + 4 x 2 − 2 x 3 in terms of equation by using slack variable and surplus variable subjected to, − 2 x 2 + 5 x 3 ≥ 8 4 x 1 − x 2 + 3 x 3 ≤ 12 and x 1 ≥ 0 , x 2 ≥ 0 , x 3 ≥ 0 .

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To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to,

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0.

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0

Want to see the full answer?

Chapter 7 Solutions

The problem z = − 5 x 1 + 4 x 2 − 2 x 3 in terms of equation by using slack variable and surplus variable subjected to, − 2 x 2 + 5 x 3 ≥ 8 4 x 1 − x 2 + 3 x 3 ≤ 12 and x 1 ≥ 0 , x 2 ≥ 0 , x 3 ≥ 0 .

Videos

To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to, −2x2+5x3≥84x1−x2+3x3≤12 and x1≥0,x2≥0,x3≥0.

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to −2x2+5x3≥84x1−x2+3x3≤12 and x1≥0,x2≥0,x3≥0

Want to see the full answer?

Chapter 7 Solutions

To calculate: The problem z=−5x1+4x2−2x3 in terms of equation by using slack variable and surplus variable subjected to,

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0.

To calculate: The initial simplex tableau for equation z=−5x1+4x2−2x3 subjected to

−2x2+5x3≥84x1−x2+3x3≤12

and x1≥0,x2≥0,x3≥0