
Concept explainers
To find: x by solving the equation for 0≤x<2π .

Answer to Problem 31E
7π6 and 11π6
Explanation of Solution
Given information:
4sin2x+1=−4sinx
Calculation:
The value of x for the given equation can be evaluated as follows:
4sin2x+1=−4sinx [Add 4sinx on each side]
4sin2x+4sinx+1=0
(2sinx+1)2=0 [Using (a+b)2=a2+b2+2ab]
2sinx+1=0 [Taking square root on each side]
2sinx=−1 [Subtract 1 from each side]
sinx=−12 [Divide each side by 2]
x=7π6 or 11π6
Thus the values of x are 7π6 and 11π6 .
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