Among the given options, which temperature options would decrease the volume of a sample of gas base on Charles’s law has to be identified. Concept Introduction: Charles’s Law tells that the relationship between temperature and volume of a gas. The law states that at constant pressure the volume of a fixed amount of gas is directly proportional to the temperature in Kelvin units. The mathematical expression for the relationship between volume and Kelvin temperature according to the Charles’s law can be shown as follows, V 1 T 1 = V 2 T 2 Where, V 1 = T h e v o l u m e o f a g a s a t a g i v e n p r e s s u r e . T 1 = T h e K e l v i n t e m p e r a t u r e o f t h e g a s . V 2 = T h e v o l u m e o f t h e g a s u n d e r a n e w s e t o f c o n d i t i o n s . T 2 = T h e K e l v i n t e m p e r a t u r e o f t h e g a s u n d e r a n e w s e t o f c o n d i t i o n s .

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Chapter 7.5, Problem 2QQ

Interpretation Introduction

Interpretation:

Among the given options, which temperature options would decrease the volume of a sample of gas base on Charles’s law has to be identified.

Concept Introduction:

Charles’s Law tells that the relationship between temperature and volume of a gas. The law states that at constant pressure the volume of a fixed amount of gas is directly proportional to the temperature in Kelvin units. The mathematical expression for the relationship between volume and Kelvin temperature according to the Charles’s law can be shown as follows,

V1T1=V2T2

Where,

V1 = The volume of a gas at a given pressure.T1 = The Kelvin temperature of the gas.V2 = The volume of the gas under a new set of conditions.T2 = The Kelvin temperature of the gas under a new set of conditions.

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