Explanation Given: Trigonometric Quadratic equation tan 2 θ = ( 3 / 2 ) × sec θ , 0 ≤ θ < 2 π . Calculation: tan 2 θ = ( 3 / 2 ) × sec θ -----1. Using identities, 1 + tan 2 θ = sec 2 θ Therefore, tan 2 θ = sec 2 θ − 1 Using this formula in equation 1, = sec 2 θ − 1 = ( 3 / 2 ) × sec θ Multiplying by 2 on each side, = 2 sec 2 θ − 2 = 3 sec θ Subtracting 3 sec θ on each side, 2 sec 2 θ − 3 sec θ − 2 = 0 Quadratic equation is in the form of sec function can be factored. 2 sec 2 θ − 4 sec θ + sec θ − 2 = 0 Taking the common factor 2 sec θ from ( 2 sec 2 θ − 4 sec θ ) and + 1 from (

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Author: Michael Sullivan

Publisher: PEARSON

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Chapter 7.3, Problem 81AYU

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To find: The trigonometric Quadratic equation in the form of ${tan}^{2} θ = (3 / 2) \times sec θ, 0 \leq θ < 2 π$ .

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Chapter 7.3, Problem 80AYU

Chapter 7.3, Problem 82AYU

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The trigonometric Quadratic equation in the form of tan 2 θ = ( 3 / 2 ) × sec θ , 0 ≤ θ < 2 π .

Solution Summary: The author explains the trigonometric quadratic equation tan 2 = ( 3 / 2)'sec', and how it can be factored.

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To find: The trigonometric Quadratic equation in the form of ${tan}^{2} θ = (3 / 2) \times sec θ, 0 \leq θ < 2 π$ .

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Chapter 7 Solutions

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The trigonometric Quadratic equation in the form of tan 2 θ = ( 3 / 2 ) × sec θ , 0 ≤ θ &lt; 2 π .

Solution Summary: The author explains the trigonometric quadratic equation tan 2 = ( 3 / 2)'sec', and how it can be factored.

Videos

To find: The trigonometric Quadratic equation in the form of tan 2 θ = ( 3/2 ) × secθ, 0 ≤ θ < 2π .

Want to see the full answer?

Chapter 7 Solutions

Additional Math Textbook Solutions

The trigonometric Quadratic equation in the form of tan 2 θ = ( 3 / 2 ) × sec θ , 0 ≤ θ < 2 π .

To find: The trigonometric Quadratic equation in the form of ${tan}^{2} θ = (3 / 2) \times sec θ, 0 \leq θ < 2 π$ .