Chapter 7.2, Problem 72E

To determine

To compute U if the bulb remains opens for 5 hours, where U is the energy (in joules) expended by the bulb over a period of time T second is,

$U={\displaystyle \underset{0}{\overset{T}{\int }}P(t)dt}$, where $P=\frac{V^2}{R}$ is power(J/s), $R=144\Omega$ and voltage varies as $V=V_0(2\pi ft)$

$V_0=110V,f=60Hz$