
Concept explainers
(a)
Use the Distributive property to write 12(24−h) as an equivalent algebraic expression.
288−12h
Given information:
The expression, 12(24−h)
Concept used:
- The distributive property of binomials (FOIL): (a+b)(c+d)=a⋅c+a⋅d+b⋅c+b⋅d
- Left Distributive property: a(b+c)=a⋅b+a⋅c
- Right Distributive property: (a±b)c=a⋅c±b⋅c
- Exponent property: xn⋅xm=xn+m
Calculation:
In order to simplify the given expression 12(24−h) , first use the distributive property to expand the parenthesis and then simplify further by using the exponent property as shown below
12(24−h)=12(24−h)=12(24)+12(−h)=288−12h
Thus, the given expression simplifies to 288−12h .
(b)
Make a table of ordered pairs of (h,v) of the equation 288−12h .
h | v | (v,h) |
0 | 288 | (0,288) |
1 | 276 | (1,276) |
2 | 264 | (2,264) |
3 | 252 | (3,252) |
4 | 240 | (4,240) |
Given information:
The expression, 288−12h
Explanation:
In order to make a table for v,h by using the expression v=288−12h ,putting any value of h to get the value of v. So, the table is :
h | v | (v,h) |
0 | 288 | (0,288) |
1 | 276 | (1,276) |
2 | 264 | (2,264) |
3 | 252 | (3,252) |
4 | 240 | (4,240) |
(c)
Graph the ordered pairs on the coordinate plane.
GIVEN:
The expression, 12(24−h)
Concept Used:
In rectangular coordinate system any point be in the form of (x,y) .
In Quadrant I, both the coordinates of ordered pair are positive, that is, (+,+) .
In Quadrant II, first number is negative and second is positive, that is, (−,+) .
In Quadrant III, both the coordinates of ordered pair are negative, that is, (−,−) .
In Quadrant IV, first point is positive and second is negative, that is, (+,−) .
Explanation: In order to plot the point (0,288) , observe that both numbers of the ordered pair are positive, so the point will be in first quadrant.To plot the graph of the point, first move 0 units to the right starting from origin and then move 288 units up.
In order to plot the point (1,276) , observe that both numbers of the ordered pair are positive, so the point will be in first quadrant.To plot the graph of the point, first move 1 units to the right starting from origin and then move 276 units up.
In order to plot the point (2,264) , observe that both numbers of the ordered pair are positive, so the point will be in first quadrant.To plot the graph of the point, first move 2 units to the right starting from origin and then move 264 units up.
In order to plot the point (3,252) , observe that both numbers of the ordered pair are positive, so the point will be in first quadrant.To plot the graph of the point, first move 3 units to the right starting from origin and then move 252 units up.
In order to plot the point (4,240) , observe that both numbers of the ordered pair are positive, so the point will be in first quadrant.To plot the graph of the point, first move 4 units to the right starting from origin and then move 240 units up.
The graph of the point is shown below:
(d)
Explain what happen to the volume as the height increases.
Given information:
The expression, v=12(24−h)
Explanation:
If the height of the volume increases then there volume will be decreases because of the equation given v=12(24−h) .
Chapter 7 Solutions
Glencoe Math Accelerated, Student Edition
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