Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one
enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenyl-1-propanol.
(a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates-the
product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon.
H Br
он
H20
1-bromo-1-phenylpropane
1-phenyl-1-propanol
observed [a) = +5.0
optically pure S isomer, [a] =-48
%3D
In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer ispresent. For example, treatment of optically pure 1-bromo-1phenylpropane with water forms 1-phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates—the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon.
In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1- phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Whichproduct predominates—the product of inversion or the product of retention of conguration? (c) Suggest an explanation for this phenomenon.
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- In some nucleophilic substitutions under SN1 conditions, completeracemization does not occur and a small excess of one enantiomer ispresent. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data.(b) Which product predominates—the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon.arrow_forward(a) What product(s) are formed when the E isomer of C6H5CH = CHC6H5 is treated with Br2, followed by one equivalent of KOH? Label the resulting alkene(s) as E or Z. (b) What product(s) are formed when the Z isomer of C6H5CH = CHC6H5 is subjected to the same reaction sequence? (c) How are the compounds in parts (a) and (b) related to each other?arrow_forwardWhen treated with NaOH, the bromide below gives an alkene by the E2 mechanism, by elimination of the H atom indicated by the arrow: (a) Draw the Newman projection from which elimination takes place. (b) Draw the mechanism. (c) Draw the product with the proper stereochemistry. (d) Assign the proper stereochemical descriptor to the product. (e) Give the rate equationarrow_forward
- When 2-bromo-3-phenylbutane is treated with sodium methoxide, two alkenes result (by E2 elimination). The Zaitsevproduct predominates.(a) Draw the reaction, showing the major and minor products.(b) When one pure stereoisomer of 2-bromo-3-phenylbutane reacts, one pure stereoisomer of the major product results.For example, when (2R,3R)-2-bromo-3-phenylbutane reacts, the product is the stereoisomer with the methyl groups cis.Use your models to draw a Newman projection of the transition state to show why this stereospecificity is observed.(c) Use a Newman projection of the transition state to predict the major product of elimination of (2S,3R)-2-bromo-3-phenylbutanearrow_forwardThe bicyclic heterocycles quinoline and indole undergo electrophilic aromatic substitution to give the products shown. (a) Explain why electrophilic substitution occurs on the ring without the N atom for quinoline, but occurs on the ring with the N atom in indole. (b) Explain why electrophilic substitution occurs more readily at C8 than C7 in quinoline. (c) Explain whyelectrophilic substitution occurs more readily at C3 rather than C2 of indole.arrow_forwardWhen 2-bromo-3-phenylbutane is treated with sodium methoxide, two alkenes result (by E2 elimination). The Zaitsevproduct predominates.(a) Draw the reaction, showing the major and minor products.(b) When one pure stereoisomer of 2-bromo-3-phenylbutane reacts, one pure stereoisomer of the major product results.For example, when (2R,3R)-2-bromo-3-phenylbutane reacts, the product is the stereoisomer with the methyl groups cis.Use your models to draw a Newman projection of the transition state to show why this stereospecificity is observedarrow_forward
- Rank the compounds in each group in order of increasing reactivity in electrophilic aromatic substitution: (a) C6H6, C6H5Cl, C6H5CHO, C6H5OCH3; (b) C6H5CH3, C6H5NH2, C6H5CH2NH2, C6H5CONH2.arrow_forwardH 9. (a) Optically active 2-bromobutane undergoes racemization on treatment with a solution of KBr. Give a mechanism for this racemization. (b) In contrast, optically active butan-2-ol does not racemize on treatment with a solution of KOH. Explain why a reaction like that in part (a) does not occur. (c) Optically active butan-2-ol racemizes in dilute acid. Propose a mechanism for this racemization.arrow_forwardThe bicyclic heterocycles quinoline and indole undergo electrophilic aromatic substitution to give the products shown. (a) Explain why electrophilic substitution occurs on the ring without the N atom for quinoline, but occurs on the ring with the N atom in indole. (b) Explain why electrophilic substitution occurs more readily at C8 than C7 in quinoline. (c) Explain why electrophilic substitution occurs more readily at C3 rather than C2 of indole.arrow_forward
- The reaction of butan-2-ol with concentrated aqueous HBr goes with partial racemization, giving more inversion thanretention of configuration. Propose a mechanism that accounts for racemization with excess inversion.(b) Under the same conditions, an optically active sample of trans-2-bromocyclopentanol reacts with concentrated aqueous HBr to give an optically inactive product, (racemic) trans-1,2-dibromocyclopentane. Proposea mechanism to show how this reaction goes with apparently complete retention of configuration, yet withracemization. (Hint: Draw out the mechanism of the reaction of cyclopentene with Br2 in water to give thestarting material, trans-2- bromocyclopentanol. Consider how parts of this mechanism might be involved in thereaction with HBr.)arrow_forwardThe alkene shown undergoes bromination. H (a) Draw the product(s) of bromination of this compound, including all expected stereoisomers (if any). Use wedge-and-dash bonds to designate the stereochemistry at any chirality centers, and make sure to draw an explicit hydrogen if a chirality center has one. (b) Characterize the starting alkene as having the E or Z configuration. (c) characterize the product(s). (a) H Br₂ Draw the product(s) of bromination. Br H Brarrow_forward(a) Show how you would synthesize the pure (R) enantiomer of 2-butyl methyl sulfide, starting with pure (R)-butan-2-oland any reagents you need.(b) Show how you would synthesize the pure (S) enantiomer of the product, still starting with (R)-butan-2-ol and anyreagents you need.arrow_forward
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