Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 7, Problem 7.15P
To determine
Find the hydraulic conductivity of the sand at porosity of 0.45.
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a wet sand sample has a volume of 4.6 x 10^-4 m^3 and weighs 8.1 N. After oven-drying, the weight reduces to 7.5 N. Use Gs=2.59.
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Chapter 7 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 7 - Prob. 7.1PCh. 7 - Prob. 7.2PCh. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10P
Ch. 7 - Prob. 7.11PCh. 7 - Prob. 7.12PCh. 7 - Prob. 7.13PCh. 7 - Prob. 7.14PCh. 7 - Prob. 7.15PCh. 7 - Prob. 7.16PCh. 7 - Prob. 7.17PCh. 7 - Prob. 7.18PCh. 7 - Prob. 7.19PCh. 7 - Prob. 7.20PCh. 7 - Prob. 7.21PCh. 7 - Refer to Figure 7.24. The following data were...Ch. 7 - Prob. 7.23PCh. 7 - Prob. 7.1CTP
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- be the hydraulic conductivity at 20°C? Ans. 1.0 x 10 cm/sec 4. For a normally consolidated clay, the following values are given. k(cm/sec) 0.45 x 10 e 0.78 1.1 0.88 x 10 Estimate k at a void ratio of 0.97 6.0089 107arrow_forwardDry Sand H Groundwater Table Clay H, Refer to the soil profile shown. Given H1 = 9.46 m., and H2 = 4.79 m. If the ground water table rises by 2.58 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.57, e = 0.63. Properties of clay: Gs = 2.74, e = 0.88. Round off to two decimal places.arrow_forward6.5 Refer to Figure 6.4. For a constant head permeability test in a sand, the following values are given: • L = 350 mm • A= 125 cm² • h = 420 mm • • Water collected in 3 min = 580 cm³ Void ratio of sand = 0.61 Determine: a. Hydraulic conductivity, k (cm/s) b. Seepage velocity dified conarrow_forward
- Given the following: H1 = 1.5 m H2 = 3.0 m H3 = 2.0 m K1 = 0.001 cm/sec K2 = 0.032 cm/sec K3 = 0.000041 cm/sec 1. Find the effective average permeability of the deposit in the horizontal direction. (in cm/s) 2. Find the effective average permeability of the deposit in the vertical direction. (in cm/s) 3. What is the ratio of the equivalent hydraulic conductivity?arrow_forward[Seepage] tank shown below. For the sand, the following properties are given: e = 0.40 , G.S = 2.67 . Calculate the effective stress at A. a. Consider the upward flow of water through a layer of sand in a 1.2m Overflow 0.7 m Sand z = 0.9m 2 m Inflowarrow_forwardThere is an upward flow of 0.06 ml/s through a sand sample with a coefficient of permeability 3 × 10^–2 mm/s. The thickness of the sample is 150 mm and the cross-sectional area is 4500 mm2.Determine the effective stress in N/m2 at the bottom the sample, if the saturated unit weight of the sample, is 18.9 kN/m3. Provide Diagram a.709.5 b.177.38 c.88.69 d.354.75arrow_forward
- The results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 41 cm Length of sample = 66 cm Constant head difference = 30 cm Time of collection = 473 secs Weight of water collected = 416 grams Find the seepage velocity in cm/min. if the void ratio is 0.43.arrow_forwardThe results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 31 cm Length of sample = 98 cm Constant head difference = 52 cm Time of collection = 364 secs Weight of water collected = 448 grams Find the seepage velocity in cm/min. if the void ratio is 0.33. Round off to four decimal places. Answer: 0.3943arrow_forwardQuestion 40 The results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 25 cm Length of sample = 80 cm Constant head difference = 77 cm Time of collection = 388 secs Weight of water collected = 340 grams Find the seepage velocity in cm/min. if the void ratio is 0.49. Round off to four decimal places.arrow_forward
- 2.11 A sand has the following: D10 = 0.2 mm, Dø = 0.4 mm, and void ratio e = 0.6. a. Determine the hydraulic conductivity using Eq. (2.38). b. Determine the hydraulic conductivity using Eq. (2.40).arrow_forward21 The results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 37 cm Length of sample = 92 cm Constant head difference = 78 cm Time of collection = 337 secs Weight of water collected = 375 grams Find the seepage velocity in cm/min. if the void ratio is 0.6. Round off to four decimal places.arrow_forwardstion 17 | Dry Sand H Groundwater Table Clay Refer to the soil profile shown. Given H1 = 8.93 m., and H2 = 5.32 m. If the ground water table rises by 2.01 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.56, e = 0.65. Properties of clay: Gs = 2.72, e = 0.87. Round off to two decimal places.arrow_forward
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